First order homegenous equations
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Thank Khan, you just taught me solving diffy Q by substitution.
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are you supposed to know the F at the beginning or later?
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The "+c" could have been put into the ln() by imagining it to be c= ln(A), where A is just another constant. This gives you a final answer of xln(Ax). That tidies it up a bit. Fantastic videos, keep it up!
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Hey Khan,
Where can i find reference of that way of checking for homogeneity 'F(x\y)'? I can't find it in any textbook nor any formal definition that includes it.
Thanks
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@Hamshhi chicks are awesome but if i were him i would crazy from seeing so many every day lol
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Please apply to Asian University for Women as a Math Professor ASAP. The students would be really really grateful to a professor who explains like you! Thanks for the session!
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@DTHRocket nevermind. i think the +C makes it nonhomogenous
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@DTHRocket That's a Homogeneous Linear Equation, which Sal mentioned in the beginning of the video. I guess it's completely different from a plain old Homogenous Equations.
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I love you khan Academy!!!! (no homo) I wish my professor explains like you.
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Khan corrects the solution at 6:42. You are right, the solution should be y=xln|x|+xc
tuxb0x 2 years ago 25
please finish watching the video before commenting.. because he realises his mistake and correct it.. and yes.. xC cannot become just C because... C is an inmovable constant for that ecuation while.. X can take different values and the equation will hold right.. WildChildftw doesn´t know math or at list.. the antiderivatives..
gamr789 2 years ago 7