Square and Circle area calculation Problem video

Square and Circle area calculation Problem video

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• Square
• and
• Circle
• area
• calculation
• Problem
• video

[TMalliwuC]

Okay, the answer is not C. Line PR also happens to be the diameter of the circle (4). The area of a Circle is pie times radius squared, thus we halve the diameter to get the radius(2). Pie or 3.14 * 2 *2 = 12.56 - the circles area. Then we do 4*4 (or length times width), to get the area of the square =16. Next, subtract the area of the circle from the area of the square to get - 3.44. 8-2*3.14 = 1.72. But 16-4*3.14 = 3.44. Thus, the answer is D, not C.

[mathproblems]

@TMalliwuC PR is not the diameter of the circle but PS is the diameter of the circle.

PS^2+rs^2=pr^2=4^2=16, BUT PS=PR SO PS^2+PS^2=16 , PS=SQRT(8)

AREA OF THE CIRCLE= PI*8

AREA OF SQUARE=8

SHADED AREA=8-8PI , ANSWER IS C

[mathproblems]

@mathproblems AREA OF THE CIRCLE IS= PI*((SQRT(8))^2)/4 = 2PI

SHADED AREA = 8-2PI WHICH IS THE ANSWER C

[mathproblems]

@TMalliwuC PR IS NOT THE DIAMETER OF THE CIRCLE PS IS THE DIAMETER OF THE CIRCLE VALUE OF PS FROM TRIANGLE PRS CAN BE CALCULATED BY USING PUTHOGOREAN THEOREM PR^2=PS^2+RS^2 4^2=PS^2+RS^2 (SINCE PS=RS) 16=2*PS^2 PS^2=8 PS=SQRT(8) PS=2SQRT(2), RADIUS =SQRT(2) AREA OF CIRCLE-PI*R^2 AREA=PI*2, SQUARE AREA=2SQRT(2)*2SQRT(2)=8 SO SHADED AREA =8-2*PI WHICH IS CHOICE C AND NOT D

[KiteFlyingMe]

HOW COULD I POSIBLY SOLV THIS!!!!....

[8osiris]

w w w.flickr.com  /photos /sacred_geometry /5497024890/

This is how you really Square the Circle

[Darko2625]

@nagu222 Answer? Are you nuts?

[nagu222]

Stupid

Where is the answer?

[LTMY]

@lnpkural the last second step of your calculation is wrong. r^2+r^2 DOES NOT EQUAL TO 4, It should be 4^2

[lnpkural]

Its a simple problem, lol.. Even so many cant resolve it correctly.. The answer is c (8-2pi) Demo : r: Circle radius. Circle area: pi*r*r (pi*R^2) Square surface: (2*r)^2 Shaded area : Square surface - circle area= 4r^2-pi*r^2 = r^2(4-pi) Let's find r.. The sulbasutra formula, a^2+b^2=c^2 (also called Pythagorem's theorem) is applicable here as there are 90 degree angles.. So we have : r^2+r^2=2^2=4 => 2*r^2=4 => r^2=2 => r=sqrt(2) Apply the result..in r^2(4-pi)=asked area