Lec 13 | MIT 18.03 Differential Equations, Spring 2006
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@gorgolyt No, he has it right. We want the imaginary part, aka the part with factor i.
The imaginary part of (1+i)(cos(x) + i sin(x)) is cos(x) + sin(x).
If we were looking for the real part, then indeed it would be cos(x) - sin(x).
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also ich bin blond
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@RinaldiMeteoric It's the 6th. And by the way, you're the laziest folk i've ever seen !
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Equations make me dizzy. Hahahah
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Which lesson should I watch to learn how to "complexfy" as the professor does at 17:58. Thank you very much.
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can someone tell me if that is first or second semster or whatever..?
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the only reason i clicked on like on this video is when he mention it wants to be T but i make it X . lol funny. he is funny teacher.
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@farzadaf No, +sin is correct. If you expand out the terms (1+i)(cos x + i*sin x), you get (cos x - sin x) + i*(cos x + sin x). The particular solution takes only the imaginary part, the term (cos x + sin x), discarding the real part (cos x - sin x).
This is because the original ODE (y) became the imaginary part of the "complexified" ODE (y-tilde).
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yes I got -sin(x) as well
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woot he's wearing my favorite jacket again!!!
Liaomiao 8 months ago 3
savior during finals
longshot1710 1 year ago