Factoring the hard trinomial using "triple play"

How to use the "triple play" technique ( little bit of magic) to factor a hard trinomial. This video is the 12th out of 16 in the Factoring series. The other three series are "Solving Equations", "Word Problems" and "Graphing".

Category:

Howto & Style

Tags:

• mathematics
• factoring
• series

[katylyssiesmom2]

Do you have a video for setting it to zero or using the zero method?

[minkusbc]

@katylyssiesmom2 Yes, see my video on solving quadratic equations by factoring - minkusbc

[TINBITZPHAM]

How about 4x^2+x-3?

what number will multiply to 12 and equals 1?

[minkusbc]

Must multiply to make 12 and subtract to make +1. Thus +4 and - 3 will work.

[krazyliljoo]

5n squared+10n+20?

nothing equals 10

2*50

4*25

5*20

10*10

[minkusbc]

It's not really a hard trinomial because it has a common factor of 5. Take out the 5 and you have

5n^2 + 10n + 20 = 5(n^2 + 2n + 4). Since there are no two numbers that multiply to make 4 and add to make 2, you can go no further.

[frankprime]

OMG it works, why is my teacher such a dumb bitch?

[benwood241]

The triple play method saved my ass.

[ryanalbertmills]

can you use this method to factor any trinomial?

[mitchelllll99]

this guy gets alll the bitches

[jgrande345]

Does this method work for (ax^2) or the (c) in the formula, or just (bx)?

[PeaceAndTaylor]

omg thank you so much.

[Adrammalech7570]

Good god, burn the textbooks, ditch the classes and sub to this guy.

[myassin2009]

@kps1215 Do you still need help lol?

[Paradiddleshufflin]

My algebra 2 teacher < Minkusbc

[controlledchaosCO]

Thank you so much for posting! Saved my life!

[kps1215]

i have a ? on my HW that I am totally stumped on: 6y`2 - 13y - 5. I did your triple play method and it came out to:

(6 y + 2) (6y - 15)

------------------------ 6

and neither side is divisible by 6!

Please help me! I'm desperate and this is literally the only ? i couldn't get using this method!!! am I doing something wrong, or do I have to do something differently to solve with - signs??

THANKS

[bouich29]

woow , i have a way that is soo much easier than this .