free energy overunity device Muller type motor generator with extra magnets
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Top Comments
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This seems reminiscient of a Searl effects generator to me.
All Comments (32)
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@chapmansbg What will happen is that it will grind to a halt, you cannot produce energy like this, it is not possible. If it were possible all the coal fired power stations would become redundant overnight.
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Input power goes from 11.8 to 11.3 W as output power (light) goes from zero to 22.2 W. This indicates COP of 1.96. Thanks for posting!
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what happen wen battry goes down charge ??? lol
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your battery dude you running to a battery
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In this video: Inputs = 12.57vdc & 0.92a. Outputs (with 12v automotive lamp) = 12vdc & 2.0a.
This, to me, shows over-energy.
I noticed for a little while when he connected the lamp that the Input dropped to 12.30vdc & 0.92a.
Anybody know what the wattage rating is for one of those 12vdc automotive bulbs?
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I watched the self-running video and took notes. When the unit was at full speed, I saw that the rail voltage was 15.07vdc which is what was across the capacitor. The power switch is between the rail and the capacitor. That's why the power LED on the converter remains on after he turns the switch off. The capacitor is discharging .The voltage at the output of the Vanson SDR-3000 converter was 12.02vdc. Before he connected the lamp, the amp-meter read 1. After he connected the lamp, it read 2.8.
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This video wasn't worth my time, go on, skip to the next one because there is no overunity with the battery cable on.
In short... F A I L !!
However, output looping into input is what you should focus on.
I'm gonna build my first electromagnetic motor now, but i'll also amplify its power tremendously, say 60 kg push/lift force should be good, but not enough.
More magnets and bearings.
It should have enough force AND power to get a plane up in the air and i know its possible.
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instead of running the light bulb, connect the output to the input to see what happens
Why does the volt meter drop down from 12.57v (no bulb) to 12.29 volts every time he turns on the light bulb? The current meter shows a slight drop in current to the motor. This means the battery has a load on it when the bulb is on because of the voltage drop, but the motor in the generator is not pulling the current. Must be the light bulb pulling the current from the battery, but not showing the current flow through the digital amp meter. That appears to be what the meters are telling us.
LibertyMagnetMotor 9 months ago
@LibertyMagnetMotor
Well he siad he had an additional recovery diode to the plus pole of the battery.
So when the load was applied the voltage did not suffice to support the battery any further via this recovery diode
that clamped the output voltage to the battery voltage...
So this can be then a valid explanation why we see the voltage drop...
Regards, Stefan.
overunitydotcom 9 months ago