Lagrange multipliers: Extreme values of a function subject to a constraint
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Uploader Comments (DrChrisTisdell)
All Comments (17)
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Wow Dr. Tisdell you are a remarkable prof! Even though I just came here for review after having learnt this already, I can tell all viewers that this is a spot on example/explanation of Lagrange multipliers! I wish you were a professor at Concordia University in Montreal, I would love to have you as a prof one day!
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Perfectly explained! I came here clueless after 2 hours in the textbook and left 7 minutes and 31 seconds later with full understanding
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oh yeah !!! thank u
DrChrisTisdell it's very clear!
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Hi Yoyaya. If you listen carefully, at 6.42 I discuss how to show which points lead to maxima and which points lead to minima.
In particular, if you evaluate $f$ at the first two points then you get $1/(2\sqrt{2})$. At the other two points $f$ has value $-1/(2\sqrt{2})$. It is easy to see that the maximum of these set of values is $1/(2\sqrt{2})$ and the minimum value is $-1/(2\sqrt{2})$. Thus, the 2nd-derivative test is not required.
Hope I am being clear here and thanks for watching!
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The hum in the background sounds like a UFO is ready to land.
swampwiz 1 year ago
@swampwiz Haha! Actually, it is the noise from the air-con units for the building that lie directly outside the window.
DrChrisTisdell 1 year ago
Perfect!!! Thanks a lot
ulivaldo 2 years ago
Great!! Thanks!
DrChrisTisdell 2 years ago
Is that how you pronounce Lagrange at 0:57 ? I said it that way and my tutor gave me the dirty haha :)
PcKSnipE 2 years ago
Hahaha!!! So much for my Aussie-French accent??!! :-)
DrChrisTisdell 2 years ago