3 octave arpeggio of Phrygian on a 7 string Ibanez in M3 tuning

3 octave arpeggio of Phrygian on a 7 string Ibanez in M3 major-third tuning, ring finger leading and the root being A

The number of modes in 3 octaves is equal to the number of notes including the root times 2 plus 1.
In this example I am playing 15 modes across 7 stations 2 frets from string to string, therefore
moving 12 frets across the 7 strings and the root being played on the high string with the same
finger as the root being played on the low string.

Phrygian having 7 notes including the root, times 2 plus 1 equals 15 modes across 3 octaves,
and with 7 stations - I have divided the modes like this:

1 2 modes
2 2 modes
3 2 modes
4 3 modes
5 2 modes
6 2 modes
7 2 modes

Because, it is best to stagger these modes in a symmetric way, so that the staggering of modes is the same ascending as descending - and in arpeggios
the fingering ascending DOES ALWAYS MATCH the fingering descending owing to the fact that we are
cycling through the 2 octave modes in an arpeggio - whereas in a straight 3 octave run through the scale
the pattern mapping is more complex and therefore ascending usually does not match descending.

If it was a pentatonic I would do it like this, 5 times 2 plus 1 equals 11 so,

1 1 modes
2 2 modes
3 2 modes
4 1 modes
5 2 modes
6 2 modes
7 1 modes

Etc,

Category:

Music

Tags:

• major-3rd-tuning
• 3-octave-arpeggio
• 7-string-Ibanez-guitar
• Phrygian