Proving the Chain Rule
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But isn't the chain rule just fprime(g(x_0)) * gprime(x_0) ? If you multiply it by h then won't that be like multiplying by 0?
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Woah that is some amazing free hand sketch
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can you make a pre-calculus video for beginners? y knot! (bad nerd jock)
abeeraj 1 month ago
@abeeraj There is a whole series in two different play lists.
ProfessorElvisZap 1 month ago
At 9:05 to 9:15 you rewrite (lets use e instead of epsilon): e(k)/h as e(k)/k * k/h
and then look at the limit as h goes to zero.
But since k=g(x0+h)-g(x0) there is a risk that k is zero. In fact if g is a constant
funktion, then k is zero for all values of h.
jasoegaard 7 months ago
@jasoegaard Your point is well taken. If g(x) is a constant, then the issue becomes trivial. Similarly, if e(k) is small in comparison to k, then if k is 0, e(k) must also be 0.
ProfessorElvisZap 7 months ago
from 3:45 to 4:10, why is f is a function of y and not x?
lamarjlp914 2 years ago
Because its domain will be the range of g. Initially, I wrote it as x_0, and then replaced x_0 with y_0. Indeed, the variable's name does not matter, but observe that I substitute in for y_0=g(x_0) later.
ProfessorElvisZap 2 years ago