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Proving the Chain Rule

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Uploaded by on Aug 14, 2008

Professor Zap shows how to prove the chain rule using differentials.

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Education

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Uploader Comments (ProfessorElvisZap)

  • can you make a pre-calculus video for beginners? y knot! (bad nerd jock)

  • @abeeraj There is a whole series in two different play lists.

  • At 9:05 to 9:15 you rewrite (lets use e instead of epsilon): e(k)/h as e(k)/k * k/h

    and then look at the limit as h goes to zero.

    But since k=g(x0+h)-g(x0) there is a risk that k is zero. In fact if g is a constant

    funktion, then k is zero for all values of h.

  • @jasoegaard Your point is well taken. If g(x) is a constant, then the issue becomes trivial. Similarly, if e(k) is small in comparison to k, then if k is 0, e(k) must also be 0.

  • from 3:45 to 4:10, why is f is a function of y and not x?

  • Because its domain will be the range of g. Initially, I wrote it as x_0, and then replaced x_0 with y_0. Indeed, the variable's name does not matter, but observe that I substitute in for y_0=g(x_0) later.

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All Comments (9)

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  • But isn't the chain rule just fprime(g(x_0)) * gprime(x_0) ? If you multiply it by h then won't that be like multiplying by 0?

  • Woah that is some amazing free hand sketch

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