Integration Using method of Partial Fractions
Uploader Comments (patrickJMT)
Top Comments
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@ryezizzle none. i studied.
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thanks for being one of the only people willing to volunteer their time to help others with math! I wish there were more people motivated by helping others instead of by money like you...it's a huge help man, thanks a ton
All Comments (84)
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where does the single x term come from? im confused
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@lilangel0072 Why are you such a douche?
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@attentionwhoreusa, its A/X because when you break up the equation into partial fractions, the rule is to break up x^2 to (A/X)+(B/X^2) and so on, its just how the rule works for solving partial fractions
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why is the first term A/x? shouldnt it be A/x^2 ? Where are u getting the lone x? thanks
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Whoa-whoa-whoa! I got A=-1. And I did it the long way. And I checked it on my calcultor (I let x=2). [Also: I'm viewing this on my iPod Touch. So: if there are any annotations correcting this or a lot of older comments already pointing this out. Then my bad. I can't see it.]
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is the corrected video available?
if yes please link me, appreciate it :)
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Patrick! You just don't know how much you have me feeling so comfortable with partial fraction decomposition. When I went through Calculus 2, I learn it just enough to do the problems, but still was weak with it foundation-ally. I watched 3 videos thus far, this being the third and I feel like a pro at his stuff. You explain it OH SO WELL. I can't believe all this time I was scared by it going through my math classes, and when I hit ODE's, I needed it once again. The dread, but made it out fine.
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@chadbowman0 I took calc 2 last year...and it was easy, this also happened to be the easiest part in the whole course. Just because u found it a challenge doesn't mean it is one.
this video is just incredible
Kratos0909 5 months ago 4
@Kratos0909 glad you like it ; )
patrickJMT 5 months ago
what if instead of the denominator having a squared expression it had a squared one? ie (x+1)^2 vs. (x+1)^1/2?
janedoherty101 10 months ago
@janedoherty101 do you mean a square root instead of a squared expression? if so, that totally changes the problem. it just depends on the problem at that point. in the case you mentioned though : (x+1)^1/2, you can do a rationalizing substitution in some situations
patrickJMT 10 months ago
u didnt explain integration by partial fractions u just did an example ... i still dont get it :(
wintermonie 1 year ago 14
@wintermonie ok
patrickJMT 1 year ago