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The Derivative of the Square Root Function, Part 1 of 2, from Thinkwell's Calculus Video Course

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Uploaded by on Sep 14, 2010

http://bit.ly/qXO9hX Try Thinkwell Video Calculus for Free. Click this link to try Thinkwell free, no credit card required.

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Uploader Comments (ThinkwellVids)

  • lol!! im gonna have a test on derivative in a couple of hours. this freaking helped me!! even my notes arent as clear as your explanation!

  • @HiJaayD Glad our video could help!! Good luck on your test!

  • yesss!!!

  • @sjluvdance You are quick! I just uploaded it! Look for part 2, it's up now as well.

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All Comments (21)

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  • I LOVE YOU!!! No, seriously, as a 37 yo mom of 6 who is back into University Calculus, you are sure helping me out!! Thanks!

  • "well there's the zero over zero, it's sort of like a hunting game, can you hunt down the zero over zero that makes this indeterminate form? i think this is great fun don't you think this is fun!!!!!!"

  • these videos are life savers!!!!

  • thankyou!

  • He makes me feel like the 80's

  • @GrobeNuuk Awesome, appreciate it.

  • @Melee2Kil

    1/x^3 is the same as saying x^(-3)

    So like before, using the exponential rule the derivative is: -3x^-4

    Another way of writing that would be: -3 / x^4

  • @GrobeNuuk Thanks alot, the other one is 1 over X^3

  • @Melee2Kil

    sqrt(x^6): That becomes x^3 and the derivative is therefore 3 * x^2

    Are the rest questions are just your version of the problem?

  • Questions --> Quite simple stuff really compared to this, but...

    sqrt(x^6)

    1

    ---

    X^3

    Can you please tell me the derivative of these?

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