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Pressure Vessel with Torque - Part 1 - Finding Stresses.MP4

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Uploaded by on Jan 22, 2010

This is part 1 of a two part series. This part shows how to find the stresses on a thin wall pressure vessel that is also subjected to an external torque. Note: At 6:38, I mistakenly write 0.200m for the radius. It should be 0.100m. The resulting number, 41.002 MPa, is correct.

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Uploader Comments (purdueMET)

  • Sir, your videos are just absoloutly great. I am studying aerospace engineering and your videos helped me to get 'A' grade in my 2nd year soild body mechanics exam. Thank you and please carry on with this great work!!

  • @hottscorpioo Wow. Thanks for the good news.  We professor types dig positive feedback.

  • Now I understand how to calculate normal and shear stress on a pressure vessel. Its really better than my textbook. I suggest not to re-shoot this video so that viewers can re-calculate and find it for themselves.

  • @rejzwick Thanks for the encouragement. I'm glad the video helped.  I'm planning more.

  • Very good example, one mistake was calculating the shearing stress due to the applied moment was you used the diameter 0.2 m when you should have used the radius of 0.1 m for the equation t= Tr/J

  • @buddader88 Thanks for catching this. You are right - I should have written 0.100m for the radius. The resulting number is correct, though.

    When I get some time, I need to re-shoot this video.

Top Comments

  • @purdueMET

    Thank you your videos are a huge help to my mechanics class, I wish you were my teacher and I really enjoy the videos. Very good job on your lectures and I hope you post more, its easy to make little mistakes so I am glad I am able to catch them.

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All Comments (14)

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  • I like the way you teach. My professor talks really fast and never really does problems to their extent. He assumes you know everything. he secretly hates everyone.

  • @lksjadfpjudkloo32 Thanks for the clarification. I am use to dealing the area moment of inertia. Some large horizontal pressure vessels will be supported at both ends causing this type of moment. I am not familiar of any cases where there would be a realistic rotational torsion around the longitudinal axis.

  • @baudeagle1 you're thinking of Area Moment of Inertia (I). this is the Polar Moment of Inertia (J)

    had to look it up myself....

  • I was looking at your torque value. You used a value of 32 in this problem, shouldn't this be 64? The inerta for a circle is 1/4 Pi r^4. So for a diameter this would be 1/4 pi (D/2)^4.

  • I love this teacher.

    One minor correction, while calculating the shear stress professor used 0.2 for radius. The final answer is of course correct with the correct radius 0.1

  • I just want to know how you get the small d? the given is big D and the thickness or t

  • solid mechanics is a lot easier with u teaching it

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