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Euler's Identity Song

TheSingingNerd TheSingingNerd·106 videos
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Published on Oct 16, 2012

A song about the coolest identity around!

Download the song for free:
http://thesingingnerd.bandcamp.com/al...

Lyrics:
E to the i pi is equal to negative one
Man, that is crazy, this equation can't be outdone

How'd all those con con con con constants get into one...equation
It's like a re re re reunion -- special occasion

e's the limit (as n approaches zero) of (1 + 1/n)
to the power oh oh oh to the power of n (2.71)

well, its 2.7182818284590452353602874

E to the i pi plus one is equal to zero
Forget the batman -- euler was a real life hero

I's not a real real real real number it's the square root -- of minus one
And pi's a ra ra ra ra ratio of c to d I know you're stunned

All these constants are popular (the bomb)
But this one time oh oh oh oh, but this one time we see them ensemble

E to the i pi is equal to negative one
Man, that is crazy, this equation can't be outdone
E to the i pi is equal to negative one

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Uploader Comments (TheSingingNerd)

  • lirothen

    e^(i * tau) = 1. much cooler :P

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  • TheSingingNerd

    Yeah, I've actually been convinced that in the grand scheme of things tau makes more sense.  However, I would have had to explained what tau was first, since most people are much more familiar with pi. I guess I'm just part of the problem.

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    in reply to lirothen (Show the comment)
  • DisfunctionalMisfunc

    Wouldn't e^i*tau be a little problematic since tau= 2pi? It would be e^i*tau/2 then.

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    in reply to TheSingingNerd (Show the comment)
  • TheSingingNerd

    e^(i*pi) = -1 but e^(i*tau) = 1 so they are both beautiful.

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    in reply to DisfunctionalMisfunc (Show the comment)
  • Aidan Haslam

    how can it be an identity, if there are no variables?

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  • TheSingingNerd

    As long as the equation is always true, its an identity. It's a less interesting identity since you can't plug lots of numbers into it, but its still a tautology and therefore an identity. But you make a good point.

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    in reply to Aidan Haslam (Show the comment)

Top Comments

  • TheSingingNerd

    binary solo?

    · 4

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    in reply to Riggzilla (Show the comment)
  • speadskater

    Alright, so this comes from e^(ix)=cosx+i*sinx, notice that at pi, sin is 0 so the complex term goes away. When solving a differential equation involving sine or cosine, it is easier to use this identity, then solve for the real or imaginary component. Using this, you can also form an identity for cos(x) or sin(x) in terms of e,i, and a few constants. This in turn becomes a powerful machine for generating trig identities (ever see an identity, and wonder "how did they get that?", that's how

    · 3

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    in reply to awsidney (Show the comment)

All Comments (29)

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  • DisfunctionalMisfunc

    Oh wow! Now I'm even more impressed.

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    in reply to TheSingingNerd (Show the comment)
  • woo216

    Happy 306th birthday Euler!

    · 2

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  • TheSingingNerd

    I saw?

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    in reply to minishoorange (Show the comment)
  • minishoorange

    I came.

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