Isothermal Process Example
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what your answer is V1=.007648m^3...and it EXPANDS to V2=.025m^3...AT CONSTANT TEMPERATURE OF 304 K or 31.515 degrees Celcius...what the f***...Impractical...
92310CAMILLE 2 months ago
this process is AN ISOTHERMAL NON-FLOW CLOSED SYSTEM, where Wnonflow= PVln(V2/V1). I'm confused that since the W is negative you also set the PVln(v2/V1) to negative...??I think it's ...bla bla bla
92310CAMILLE 2 months ago
BOOOOOOOOOOOOOOOORING
stripes13 3 months ago