Lec 4 | MIT 18.01 Single Variable Calculus, Fall 2007
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I am very happy to see the vidoe from you, hopefully the others also are happy for You Lec 4 | MIT 18.01 Single Variable Calculus, Fall 2007
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2 weeks ago 2
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@prantare Because delta v represents the change of the value of v from the original v(x) value (in other words, delta v = "new" v - "old" v). As delta x goes to zero, "new" v and "old" v become the same (if v is continuous at this "old" v value, by the definition of continuity), and therefore the delta v approaches zero. Make sense?
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@MegaPukpui No. It will work for the proof because when lim x->0 the proof is correct. So for derivatives, it's fine if you write that way, but otherwise the mathematical proof is wrong as it won't equate for limits other than 0.
If I'm not clear enough, you are dropping a u.deltax in the proof from thin air. Remember whatever change you make to the formula, it must equate the previous formula, and it will only equate when u.deltax = 0, that is, when lim x->0.
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Cool video
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I've just noticed that my teacher never taught me the entire steps...just the short cuts. This is great!
felix10271 2 years ago 32
Thanks for this MIT - a great aid for me.
wheelygood9 2 years ago 27