Dividing Polynomials and The Remainder Theorem Part 1

This lesson shows how to divide a polynomial by a binomial using both long division and synthetic division. The lesson also discusses the Remainder Theorem and shows how to use it to find remainders in algebraic divisions. This is the first part of a three part lesson. This video was created for the MHF4U Advanced Functions course in the province of Ontario, Canada.

Category:

Education

Tags:

• MHF4U
• Advanced
• Functions

[carlgeeznetwork]

-5x(squared)+6x(squared) is equal to x(squared?????) or it will be canceld? 3:42

[AlRichards314]

@carlgeeznetwork Yes, -5x^2 + 6x^2 = x^2

[Ghestar7]

and how the hell can 15 plus 15 be 0

[AlRichards314]

@Ghestar7 Also, in the first example, you subtract in long division, so it is 15 - 15 = 0 (not 15 + 15).

[Ghestar7]

this is crap when -5x - 6x would be -11x he said x he is a baboon!

[AlRichards314]

@Ghestar7 If you are refering to the first example, in long division you subtract (not add) the terms. So it would be -5x^2 - (-6x^2) = -5x^2 + 6x^2 = x^2.

[devleo12]

@Ghestar7 dont hate u disprespectful asshole!

[KieferMicallef]

Thank you

[MrInfinityyy]

@thisisnotjustinhi x-3=0 so x=3