Gauss Law Example 2

This clip illustrates how to use Gauss' Law to find the electric field outside and inside an insulating spherical charge of uniform charge density.

Category:

Education

Tags:

• Kiledjian
• chapter 24
• insulating charge
• gauss' law
• electric flux
• electrodynamics
• physics

[Friday2031]

Thank you soo much!! I finally understand this stuff! 10 minutes from you is like 2 hours from my prof.

[rosejack0]

Its very helpfull sir,

thank you so much for this great video.

bless u.

[somegamer1879]

Thank you, helped me "ah ha" a prob I been struggling for hours with...What's total charge on spherical shell with uniform charge density d, inner radius R, outer radius S. d=Q/V. So Vtotal=(4/3)pi*S^3 - (4/3)pi(R^3) = (4/3)pi(S^3-R^3), so Q=d*(4/3)pi(S^3-R^3).

[koikers]

Lifesaver got an exam on this stuff in just over a week and these videos make more sense than a semester of work to me. Thank you so much :D

[Kenny21fm]

This helps me way more than my teacher... thank you :)

[saharsediqi]

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[d0ugr0ck]

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[momyuliya]

Thank you for your time and effort!!!

[profbanks47j]

thank you, thank you, thank you!

[masteryigo]

thank you for helpul videos