Solutions to 2010 AP Chemistry Exam Free Response Questions | College & AP Chemistry Solutions 11
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@TrollDis For a video tutorial on thermochemistry, the definition of "system" and "surrounding" and a general discussion of the First Law of Thermodynamics, please see our Tutorial 10 on our Youtube channel.
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@TrollDis This is a point of confusion for many, and it deserves a good explanation.
In a calorimetry expt like this one that occurs in a solution, the reaction is the SYSTEM, and the SURROUNDINGS is the solution. If the rxn, (SYSTEM) is exothermic, it would release heat. The heat goes into the SURROUNDINGS -- so the solution heats up.
In this problem, the rxn (SYSTEM) is endothermic. It sucks heat out of the SURROUNDINGS -- so the SOLUTION cools.
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@igetCHEM exothermic: (of a reaction or process) Accompanied by the release of heat.
When heat is released, temperature decreases... Why is it that you say otherwise?
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Can you make it for the 2011 exam? That one was SO hard
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@igetCHEM Thank you for replying! I think I understand now!
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@mlovr4l The temperature of the solution decreases, so the solution cools down during the reaction. The reaction must be endothermic (if it was exothermic, the temperature would have gone up instead).
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Why in part c of #2 would you divide the 1300 J by the molar mass? wouldnt you multiply it since the 1300J is the heat in the reaction?
pghlaxr245 3 months ago
@pghlaxr245 The heat 1,300 J is divided by the number of moles, 0.0855, but not the molar mass (molar mass is 60.0 g/mol). The reason is this: 1.3 kJ is the delta H for 0.0855 mole or urea. But you want delta H per mole. So dividing 1.3 kJ by 0.0855 mole will give you the molar delta H (in units of kJ/mole).
igetCHEM 3 months ago
Hey for free response #1 part (c), u said the [Ag] stays the same, can u care to explain why?
NextMvP0260 10 months ago
@NextMvP0260 In a saturated solution, you have dissolved as much AgBr as you could, so the concentration of Ag+ in a saturated solution (with pure water as the solvent) is always the same. The clue that you've got a saturated solution is given by the problem saying there is some solid AgBr left in the bottom of the beaker, so you are sure that no more AgBr could dissolve further.
igetCHEM 10 months ago