Problem involving angle derived from square and circle
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114 videosGeometry- 7:51
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@PmQable1 wacom, i guess...
DeltaRazor 4 months ago
how do u have such neat handwriting on a computer
PmQable1 4 months ago
Okay this is how I did it when I paused before the hint: It's the long way around. let the radius = 1 = mAB ; then mBG = 1/2 ⇒ ∆EBG is a 30-60-90 ⇒ m∠EBG = 60° ⇒ m∠EBA = 30° ⇒ ∆BAE is isosceles ⇒ m∠BAE = 75° = m∠BEA ⇒ m∠EAF = 15° Now mAE = mED ⇒ ∆ AED is isosceles so m∠EDF =15° ⇒ m∠AED = 180° - 30° = 150°; m∠AED + m∠BEA = 225°∴ 360-225= m∠BED = 135° Oy now i can go to BED.
rhoadess 4 months ago 2
@GetMeThere1 It's the same as asking the radius of the incircle... if I'm not mistaken there's a relation between polygon areas and the radius of the incircle.
PedroGynVibes 4 months ago
You are the best mathemagician I know.
nodariel 4 months ago
Can you make a video about STAR TREK THEOREM and TANGENT CHORD THEOREM
ggmm117 4 months ago
I wonder what can be said, strictly from geometry (without trigonometry) about the maximum distance between line EC and the circle? Line EC, of course, is one side of a hexagon "fully" inscribed in circle B (i.e., the largest hexagon that can fit in circle B). I wonder what can be said about the maximum distances between regular polygons and circles they're inscribed in--without involving trig or calculus....
GetMeThere1 4 months ago
Nice! Ain't life grand?!?!
GetMeThere1 4 months ago
math be so sexy.
PmSolier 4 months ago
Gotta love the feeling when you solve one of these.
griftorifto2 4 months ago 2