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Mathematical Induction (Part II)

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Uploaded by on Feb 11, 2007

http://www.isallaboutmath.com Prove Inequality using the Method of Mathematical Induction.

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Howto & Style

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  • likes, 8 dislikes

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Uploader Comments (ynceraj)

  • I don't follow the math. Could you explain why at the n+1 step. it was 3^n *3 > 3*3k+3 instead of 3^n * 3 > 3* 3k + 1? Did it not come from 3n+1 ? so 3(n+1) + 1 did not become 3n + 3 + 1?

    Thanks,

    Sury

  • You start from 3^k> 3*k+1 and then you multiply both sides of the inequality by 3 so you get 3^k*3>(3*k+1)*3  notice the parentheses. So multiplying the right side

    3^(k+1)>3*3*k+1*3 and that is

    3^(k+1)>9*k+3. Is that better?

  • hmm it didn't occur to me before to multiply both side. I just thought you do (k+1) multiply by the coefficient but everything outside go unaffected. I suppose it make sense to multiply the whole right side by 3 since 3^k+1 really is 3^k * 3. Thanks for the clarification.

  • You multiply by 3 because is the easiest way to get 3^(k+1) from 3^k

  • dont go to fast next time tooo tooo fast I need to know what is the name of the program you used though

  • I will try to go slower next time

    really sloooow :-) just kidding

    I use Corel Painter and for screen recording

    Camtasia. Regards

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All Comments (17)

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  • the voice is slower than a tortoise, bt the explanation is faster than a ferrari in german motorways. wz completely lost

  • yes...it is balid :)

  • IT IS A GREAT VIDEO

    HELPFULL FOR THE STUDENTS WHO WERE STRUGGLING TO LEARN MATHEMATICAL CONCEPTS.

    THANKS FOR YOUR VIDEO

  • you are not a good math teacher, you do not teach math here on youtube, i....don't know what the hell you are doing, but certainly not teaching math, honestly .........you suck, maybe you would be good on ......math history maybe 

  • induction is P(1) & [P(k)-->P(k+1)]

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