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Robotic Liberation by PWP (VIC-20)

Are machines going to take over the world? A "music video" completely performed by an unexpanded Commodore VIC-20 and a 1541 disk drive. Note that there are only 5120 bytes and 1024 nybbles of RAM ...  
 
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Richardddoobies (1 day ago) Show Hide
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I still have a semi-functional VIC20. It seems to have a somewhat corrupt ROM. I didn't think it was possible.
? 3 + 5
8
READY. (now heres the issue:)
10 PRINT {Q}{Q}{Q}{E} IBM SUCKS! ";
20 GOTO 10
RUN
? SYNTAX ERROR
READY.
LIST
?SYNTAX ERROR
READY.
Damn thing seems to have lost its vocablary. But simple mathematical operations still compute.
RossJams (3 weeks ago) Show Hide
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WOW ... seriously

WOW - on an unexpanded vic 20 that is unbelieveable

that was very cool
poopskinTheLiar (1 month ago) Show Hide
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Fun fact: Computer processing power isn't supposed to surpass human brain processing power until 2038-ish. So, until 2083-ish, the 'bots behind Robotic Liberation are all stupider then us :p

Also, how would the RL react to a Cyborg? force the Cyborg to stand halfway between a human and robot city?
flygonbreloom (4 weeks ago) Show Hide
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Isn't 2038 when the 32-bit dating system for calenders is suppose to fail?

Robotic Liberators want to destroy all humans, if they're really that smart, they'll put the Cyborgs brain into a hard drive or something, but the question is...

Can the human brain be stored as a discrete sequence of 0's and 1's?
gasbit (1 month ago) Show Hide
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I can't even understand half of what has been said here.
But this demo rocks.
flygonbreloom (1 month ago) Show Hide
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Read the text while it's going.

The demos notes cite that it's a psychological effect put simply.
Richardddoobies (2 months ago) Show Hide
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I was gonna holler "FAKE!" until I read the post about streaming from a 1541. My VIC20 only held 5K... but if it was loading from a disk...
1 disk = 664 "blocks"
1 block = 255 Bytes (right?)
255 * 664 = about 170K on a disk.
Mythbusters says: doable.
newcoleco (1 week ago) Show Hide
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Yes, doable.

And as for a block size, it's 256 bytes but usually the first 2 are numbers of the next track and section (block coordinates).
Richardddoobies (1 day ago) Show Hide
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Thanks! I've been trying to figure that out since 1986. I remember it needed a byte for adressing... And (I looked) it was 604 blocks on an ancient floppy...

1 disk = 604 blocks
1 block = 254 bytes of 8 bits
1 bit = 1 bit
------------------------------ -----------
About 154K useable.
That is plenty of memory to a VIC20.
UoBtExFODA (2 months ago) Show Hide
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I love everything here, especially the text. Awesome

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