Acid-base titration problem 1

Typical strong acid-strong base calculation - find the concentration of an unknown acid or base.

Category:

Education

Tags:

• strong
• acid
• base
• titration
• neutralization

[MaJzification]

How did u get 1.04M I got 1.02M, dis is my solution 1st i worked out the number of moles of H2SO4 (0.750x0.0318)=0.023mol and times it by 2 because the molar ratio is 2:1 so the answer is n(NaOH)= 0.047 mol and then I work out the concentration 0.047/0.0459 = 1.023965142/1.02M? Plz help me what part did i do wrong

[Chem2Farr]

@MaJzification The difference is rounding. 0.750 x 0.0318 = 0.02385. Since there are three significant digits in the numbers being multiplied, you should keep a "guard digit" and keep this as 0.02385. (If you were to round to 2 "sig digs", it would properly round to 0.024 - the "8" after the "3" would round it up). Then 0.02385 x 2 = 0.04770.

0.0477/0.459 = 1.039215686 on my calculator = 1.04 rounding to 3 sig. digits.

[MaJzification]

@Chem2Farr oh I see thank you very much :D

[stevenydc]

is this always the way to determine the product other than water? Cuz i think i saw some product also contained H?

[bioenginear15]

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[zicoalame69]

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[Jordie389]

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