The Two Questions of Calculus
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I love this guy's spirit :)
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That was his average velocity. We're talking about instantaneous velocity. He could have been speeding up or slowing down during the bike ride, so the average velocity is not necessarily his instantaneous velocity at the 20 mile point.
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All Comments (112)
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@TheRedAzuki First grade as in when you arelike 8
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Is this like first grade math or something? Because this is what I did in school :o
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wishing you were my math teacher kind of hard to understant calculus at 15 =/
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Wasn't r*t average velocity and not instantaneous velocity?
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they should put a speed limit on how fast he talks, lol
he make coffee nerves
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"It was so long, by the way, nearly killed me".
heh heh ;)
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@curlyfryist awe.sweet. thank for more information.. help a lot XD
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i don't get the part where you said { D,R,T ; D=R*T ; how do change D=R*T to R=D/T}
and the last question is ,,, where do u get the Rate from..there is only distance and time... so plz help
pyepyo1 10 months ago
@pyepyo1 This is just a rephrasing of the formula. If D=R*T and you want to solve for rate, you have to isolate R. The way you do that is to divide both sides by T, R*T/T = D/T, the T’s on the side with R divide out to be 1 which leaves you with R=D/T. If you plug in distance and time into this you can easily calculate the rate.
ThinkwellVids 10 months ago
@ThinkwellVids so you mean, you get the rate from the question ? correct?
i'm just a middle school student who want to jump a head a bit.so tyvm.. ur videos are awesome. :D
pyepyo1 10 months ago
@pyepyo1 Not sure what exactly you are asking here, but as long as you have distance and time, you can calculate rate from the D=R*T formula. Glad you enjoy our videos and hope we are able to help you jump ahead!
ThinkwellVids 10 months ago
@pyepyo1in simple terms if15= 5*3 then 5=15/3
curlyfryist 10 months ago
@curlyfryist Thanks! That is the perfect explanation!
ThinkwellVids 10 months ago