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Lecture 2 - Propositional Logic (Contd.)

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Uploaded by on Nov 27, 2007

Discrete Mathematical Structures

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Education

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  • Thank you Dr. Kamala! You are wonderful and I can't thank you enough. Wonderful lecture.

  • thanks Dr Kamala

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All Comments (48)

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  • Thank you Dr.Kamala , You're The Best !

  • oh this si nice

  • wow

  • About the tourist asking for directions:

    The liar will lie about being a liar...So it seems that your single question won't work...It's actually not a single question, but two questions being asked--

    1) "Are you a liar?", and

    2) "Should i take the left road?"

    To each of them, the liar will lie.

  • Among stmts made(w.r.t stmt 2 of each person), stmt of A and stmt of B are contradicting(A said B was talking to E, B said B was not talking to E), so one of them is T, and the other is F.So now you know that stmt 2 of C and D are false(2F stmts left). So D did not commit the murder and Men did not commit the murder. Since A and C are men, and since D did not commit the murder, the murderer is B(The only woman left). Hope this helped :)

  • @simplymusicism:1st thing is that each person has stated 2 statements, as shown on board(Stmt 1 and stmt 2).As per problem stmt, there are 4 true stmts, and 4 false stmts, and there is only 1 murderer.Since every person's 1st stmt is dat he/she is innocent,and since only 1 can murder E,3 people are telling the truth(w.r.t. stmt 1) and 1 is lying(Only 1 murderer is possible).So now among stmt 2(made by all 4),3 stmts are false and 1 is true[making a total of 4T and 4F stmts].chk next comment.

  • in the murder mystery question, a can be true and b false and vice versa,

    c and d's sec statement made false as it is.. i could not understand that . Can anyone explain piz

  • nice lecture but ur accent gets in the way most of the time

  • :)

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