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Cisco Training CCNA IP Addressing - Part 5 of 5

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Uploaded by on Oct 28, 2007

Instructor John Mills CCIE #5037 takes us through an IP addressing calculation as performed by computer devices in part five of the series

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  • a little mistake

    for the 60 in binary it should be 00111100 (32+16+8+4=60)

  • To MrHeyom: Yes, I can see that now, hadn't even noticed, but some people in here are also attacking that the subnet mask should have been x.x.x.60 instead of x.x.x.56, that is why I posted the comment.

    Great video, that's amazing how something so complicated can be made so simple, you are an excellent tutor, we want more and thanks

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  • Wish i should read the comments first ,it took me alot time thinking of how the binary of 60 is with only three 1's its "00111100"

  • @nbayiha got stuck there for a moment as well, but as you've noted 1+0 = 0+0

    in 'AND'-speak....that said, this video series is a great review

  • very nice of you t help everyone . thanks

  • Define the terms to real time experience like in DSL?

  • You have to take the subnet (172.16.2.16) last number and add the binary number 1111, which will give you 31. Remember he added up all the host numbers to get 1111.

  • YOU ARE WELLCOM

  • Where did you get the broadcast address of 172.16.2.31 where did the 31 came from .. Kindly explain thank you.

  • I have never used the logical and process. This gave me some serious "AHA!" moments in learning subnet tricks. I HATE doing stuff on paper but this gave me some VERY useful tips on converting and doing addressing. THANK YOU! Great stuff.

  • i have a question plz!

    ur magic-number trick.. works on all IP classes ?! if it does.. do we always start the table with 192 on the right and start jumping depending on the subtraction? thank you

  • Nice job on parts 1-5. I like the exercises at the end as it helps yo understand what you just taught.

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