Curve Sketching Using Calculus - Part 2of 2

Curve Sketching Using Calculus - Part 2of 2. In this video I discuss the following topics to help produce the graph of a function: domain, x-y intercepts, symmetry of the function, intervals of increase/decrease, local maximums and minimums, concavity, inflection points, horizontal and vertical asymptotes (whew!). all of this is too much for one 10 minute video, so the rest is in part 2! austin math tutor, austin math tutoring, austin UT math tutor, austin UT calculus tutoring, justmathtutoring.com, austinmathtutor.com, austin-math-tutor.com, austin westlake math tutor, austin westlake calculus tutor, austin UT algebra tutor, ACC tutor, austin ACC math tutor, austin math tutoring

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[jmartr34]

Hey can you recommend any studying techniques? Great videos!



[patrickJMT]

@jmartr34 read, do problems, re-read, do more problems

[iiottoii]

If your HA is 0 then why does your graph cross 0?

[patrickJMT]

@iiottoii a graph can cross its horizontal asymptote

[fuarddy]

hey patrick im from malaysia...great vids, i got a test tomorrow hope i can ace it from studying your vids......

[patrickJMT]

@fuarddy good luck!!

[vicb0t]

who else has a calc test 2mrw?

[patrickJMT]

@vicb0t not me!

[SynpaticInc]

Thank you so much Patrick! You've been a great help throughout the semester and now as I'm reviewing for my family. Your videos are beautiful; your explanations are clear and easy to understand. If you ever write a textbook or manual let us know as I'd love to use that to supplement my classes!!

[free1here]

isn't the graph still right? that's concave down from infinity to 0

[parmi4i]

Awesome videos! But I just had a question, when you are finding the inflection points and you use a number that's less than one, lets say -1, shouldn't that be 2((-1)-3)=-8/(-1)^4)=-8? So you get a concave down? If not please explain because I don't get it otherwise!

[999m4em]

you are the best! thank you!!!!

[physicistinthemaking]

How do I know y=0 as a horizontal asymptote only applies on (-infinity,0)U(1,infinity)? ie. the curve crosses y=0 at (1,0) but can't cross it anywhere else... I guess I don't understand how it is an asymptote when the curve crosses it.