Math Induction MiniLesson
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All Comments (12)
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This was unbelievably helpful! Thank you so much for explaining this!
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How can I solve exercises like
1+2+3+...+n= Σ {above stands n; on the right i; at the bottom i=1} = [n(n+1)]/2
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yo helped me so much :) thank you man yua are genius :)
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(5^n - 1) is divisible by four by assumption. We just need to know that 5^(n+1) -1 is divisible by 4 **IF we already know** that (5^n - 1) is divisible by four. So we assume the former, derive the latter, prove it for n=1, thus it is true for n=2, so since its true for n=2 its true for n=3 and so on
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Where was the proof that (5^n - 1) was divisible by four? You only proved that it's true for 1 by substitutng 1 in the expression. You didn't prove it is true for any other 'n'.
You broke the expression down nicely to a term containing two expressions ie (4x5^n) + (5^n - 1) the first term is clearly a multiple of four therefore poved...where is the ''proof'' for
(5^n -1)? . It is true, of course but you haven't proved it. This sort of half proof is really sloppy.
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thanks alottt :) :D :)
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thank you!!
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Very helpful.
that mouse clicking is so annoying.
cqlatuu 11 months ago 3
That was good, thank you :)
MrGameOwnage 5 months ago 2