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California Standards Test: Algebra II

khanacademy khanacademy·3,519 videos
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Uploaded on Dec 21, 2008

Learn more: http://www.khanacademy.org/video?v=wz...
1-5, absolute value equations and systems of equations

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Uploader Comments (khanacademy)

  • khanacademy

    Your solution doesn't work for the first equation: 2(8)-0+3(-8) = 16 - 0 -24 = -8, not +8. The first and last equiations are parrallel planes so there is no solution.

    · 24

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    in reply to cypress kee (Show the comment)

Top Comments

  • jackuy12345

    lol i think u must be a math nerd that save the world!!!!!!

    · 15

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All Comments (31)

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  • Li Fo

    Im in algebra 1.I'm in 6th grade and I understand this.

    ·

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  • Michael Rivas

    some kids take it at 14 or 13 but it depends where you are in math

    ·

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    in reply to petejwill2650 (Show the comment)
  • William Boyle

    fail.

    ·

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    in reply to cypress kee (Show the comment)
  • petejwill2650

    i'm from the UK and would like to know, at what age do people take this test?

    Is this the equivalent to GCSE's at age 16? Thanks

    ·

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  • animechix112

    Hi, I just wanted to say that you are amazing! I love you! My friend and I are high school sophomores and we will be taking our CST's for Algebra II a week and two days from now, and we have been immensely stressed over our math CST's. Luckily, my friend found you videos! After watching this video, we are amazed at how well you teach! It's so clear and understandable.

    Anyways, we just wanted to say your awesome! Please continue to make more! Thank you for your videos!

    ·

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  • Dawon Song

    Dude, he IS right.

    ·

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    in reply to cypress kee (Show the comment)
  • decon117

    you, saved me. my teacher is no good at explaining this stuff, and he no help at all. i love you no homo.

    ·

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  • slashuur8760

    thank god for people like this

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  • SpoiledLogic

    for a problem like number 3, you can make a system of 2 linear equations with 2 unknowns like Khan did, but also you can make one equation with one unknown. Let x = # of dozens of roses Let 17-x = # of dozens of carnations. Then your equation with one unknown is 15(x) + 8(17-x) = 192

    ·

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  • SpoiledLogic

    munky445 needs to take a linear algebra course

    ·

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    in reply to khanacademy (Show the comment)
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