channeling1's channel
Loading...
0
subscribers
0
video views
-
4 months ago
Lec 6 | MIT 18.01 Single Variable Calculus, Fall 2007
Exponential and log
Logarithmic differentiation; hyperbolic functions
Note: More on "exponents continued" in lecture 7
View the complete course ...
channeling1
commented:
About channeling1's channel
more
less
at 18:37 he says that b = e if k =1 / M(2) and then moves on without explaining what he means by that. so if you take the equation kfprime (0) = kM(2) , it becomes kfprime = 1/M(2) x M(2), which is kfprime = 1. i don't really get what this accomplishes in terms of defining e. definitely agree w...