Added: 2 years ago
From: chemdog8
Views: 22,807
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  • thanks! not a boring video. . more understandable compared to videos that focused more on the face of the narrator

  • @chemdog8 Dear prof. Thanks for your video. It is very informative. Can you please understand me the difference between molecularity and the Order of the reaction? Thank you.

  • best teaching

  • baagundi bey

  • It would really help if someone would actually show how to do the steps. Not just tell what to do. Some of us don't know how to do even the basics.

  • I cant understand this douche.

  • This was VERY helpful in explaining KAPLANs explanation K [A][B]2 , but what do you mean by the rate constant varies with the properties of the molecules.

    How do I know this change?

    Where can I find Rate law problems that MCAT would use!

  • The rate of every reaction depends on the concentrations (or partial pressures) of the reactants. This dependence is described by the rate law: Rate = k [A] [B]2 Reaction rates are also dependent on things like temperature. This is described by the Arrhenius Law: k = A exp[-Ea/RT]. More detailed theories describe the dependence in terms of numbers of available states, shae of the potential energy surface, etc. For MCAT, you should know about rate laws and the Arrhenius Law.

  • @chemdog8 good 1

  • For rate law problems, see practicezone(dot)org.

  • I understand Rate Law as dscussed in Kaplan, but they did not explain Arrhenius Rate law in that area very well, or for that matter sharing a the potential energy surface.

    I will look it up a little more closely

    Thanks!

  • Chuck

    Practicezone,

    Got it thanks, I am older (47), an RRT and already did 4 semesters in a Belizean Medical only to find out that Residencies were impossible to get this way, so I must learn it as good as I can for US School...

    Thank again CHEMDOG.

    PS dont blow yourself up, HA! HA!

    I am interested in Aerospace as well, but more Ozygenation via Perfusion for Astronauts in the future

  • Thank you very much for sharing your knowledge.

  • Comment removed

  • nice but stop stuttering.

  • very useful.. thanks

  • thanks very much...you're so clear in your material you teach, no hesitation or ummms!!!

  • like it!! eassier to understand than my teachers explanation

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