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  • Thank Mr. Caruana!!!!

    I understand even better!!!

  • wow you explain this the way i can understand it! my university - its all crap

  • @ghastly123 Thanks for taking the time to let us know you liked our videos.

  • you guys are amazing!!!! thank you so much. i needed this review.

  • If anyone needs help with specific questions, send them to me for step-by-step solutions! AnswerLeak

  • Hahaha Mr Caruana reminds me of Rick Moranis from Ghostbusters =D

  • @PhysicsEH Hi, is it possible for you guys to please make another video on work and energy? My teacher doesn't explain things well enough for me about work = FD because he mentioned a dot product, and I don't know what that is, somehow it relates to cosine theta? If you could please do another video on potential vs kinetic energy, that would be fantastic. If not, don't sweat it. Thank you for the videos by the way, I feel that if I watch them, I can hopefully raise my c- Thanks again!

  • Great video but i have a quick question. In the formula what dose v mean? Is it velocity? And do the joules equal the kinetic energy?

  • This was quite helpful. if i can make a suggestion though, maybe making the vid a little bit longer so you could go into a bit more detail, like providing a question and answering it for example. but thanks!

  • Hey this is great, I appreciate it.

  • Hi. I found this video extremely helpful. Thank you so much. Can you please tell me what the second part of this video is called. I can't find it. Thank you again.

  • Thank you for all your contributions! I think when I say that I really appreciate what you do and hope you keep doing it, I say it on the behalf of all the students here! I'm looking forward to more great content :) It is rare to come across such dedicated and skillful teachers :) Hope your efforts will be recognized by a larger audience in time to come!

  • @xxxEnChantedxxx Thanks for taking the time to write such a nice comment and letting us know. Glad we could help.

  • can you provide more examples and elaborate on this section? ty!!

  • @rsjyoo Hi We will be making more videos in a few months and will try to do one on this. Sorry if that does not get done in time for you but we hope the other videos help. Best of luck with your course.

  • ur so awesome helped me so much!!!!

  • @BAMFJane Thanks for the comment. Glad to help.

  • @PhysicsEH

    Suscribed already, going back to school in august, you seem to make it very clear for me to understand, better than my old professors :D

  • @chalupa1986 Glad to help. We may be adding videos in June.

  • Hi. just wanted to ask if this only applies when there is zero resultant force and acceleration is zero? Or does is work on a body in any kind of linear motion but is only taking its velocity at that instant in time, due to energy by work done.

  • @64647936 There is an unbalanced force on the car and it is accelerating. What's nice about energy calculations is that we don't worry too much about the type of motion. We added 20J to the car by pushing it and it now has 20J of energy and so is moving with a speed that represents 20J of energy. The fact that the car was pushed and underwent acceleration until the 20J was turned into Ek does not matter much since we only have to look at if we added energy or removed it. I hope this helps.

  • @PhysicsEH Thanks!

  • @64647936 Glad to help

  • hurrah! a new vid :P

    mr. morin, do you get a new cam?

  • NEW VIDEO!

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