But I've been taught to use some sort of screw rule instead of the right hand rule... Seems a bit easier. For those who dont know how to use the right hand rule this might help. imagine turning a screw/screwdriver from a to b.. You are turning it clockwise and when you do that, the screw moves forwards so the vector is in that direction. But when you move it from b to a. It is anticlockwise and the screw moves outwards. So the vector is out of the page.
Now, I got a bit confused with the right hand rule... How the order is important? The cross product of AxB is different than the cross product of BxA? Why you choose to "assign" your index to the vector a? How you define the finger order?
but im not allowed to use touch or talk to the people around me during a test! and i cant bring a friend in with me... i guess im destined to fail at any exam with cross products... : (
Alternate method is to find the determinant - assume vector x = (a,b,c)T, y = (d,e,f)T, then the cross product of x and y is the determinant of the 3x3 matrix:
MUCH easier than the right foot rule. That was just ridiculous.
akipina 4 weeks ago
Thanks really helped alot
sopro671 1 month ago
Great video thanks.
But I've been taught to use some sort of screw rule instead of the right hand rule... Seems a bit easier. For those who dont know how to use the right hand rule this might help. imagine turning a screw/screwdriver from a to b.. You are turning it clockwise and when you do that, the screw moves forwards so the vector is in that direction. But when you move it from b to a. It is anticlockwise and the screw moves outwards. So the vector is out of the page.
xXSabzzXx 2 months ago
awesome
Elzelgator 4 months ago
i enjoyed the bonus lesson on arrows.
narutosramenbuddy 5 months ago
if "n" points into the page. wouldn't the arrow be pointing up in your 3d diagram?
chickenhuntaz 5 months ago
thank you!! u saved me from an eternal confusion of the scalar/vector product!!
flyhalfinoz 5 months ago
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Now, I got a bit confused with the right hand rule... How the order is important? The cross product of AxB is different than the cross product of BxA? Why you choose to "assign" your index to the vector a? How you define the finger order?
Dreampanos 6 months ago
Comment removed
Dreampanos 6 months ago
khan as excellent as always in his explanation
ELECTRIC67100 8 months ago
how do we find the angle between two vectors?
musicandmeareinlove 8 months ago
@musicandmeareinlove did you ever find this out? if so, tell me :D
xxilikemustardxx 6 months ago
@xxilikemustardxx yep i did
let A and B be two vectors
A=xi + yj + zk
and B= ai + bj + ck
now, A*B =A B sin (theeta) n (n gives the direction)
find the magnitude of A*B using the matrix method and equate it to A B sin (theeta)
you'll get the value of sin (theeta) then look uo in the log table and u'll get the vlue of theeta...
musicandmeareinlove 4 months ago
@musicandmeareinlove Angle?? What do you mean? Just use a protractor. Or am I missing something??
RJonStreetz 4 months ago
@RJonStreetz lol...wt if u're just given the coordinates...? in d form A=xi + yj + zk
and B= ai + bj + ck and asked to find the angle betn them? u cant always draw the vectors on d cartesian plane and measure the angle between em...
musicandmeareinlove 4 months ago
@musicandmeareinlove Oh yeah right...forgot about that....Thanks!
RJonStreetz 4 months ago
@RJonStreetz :)
musicandmeareinlove 4 months ago
reminded me of flemings right hand rule (:
anisotropicentity 9 months ago
You can also take the cross product in seven dimensions. just in case :)
nico2panama 10 months ago
I still didn't get the "Right hand rule" :p
TheFutureIsRightHere 11 months ago
why sine?
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creolawurmmbj 1 year ago
u are great at teaching, thanks!
gaypotter 1 year ago
There is no doubt whatsoever that your videos are informative.
But my word ...do you over elaborate. !
divvy1400yam600 1 year ago
thanks for the video. excellent explanation of in and out of the page! dont worry, we got it :)
92syakeer 1 year ago
i love your lessons
wingmanbros 1 year ago
isn't the formula used with cos?
onetimeuse12 1 year ago
@onetimeuse12 thats the dot product =)
Rand0mAsian 1 year ago
wait....so if i have b x a instead of a x b the 25 would be a vector outta the page?
13000000a 1 year ago
.....this concept sounded mysterious and difficult until I watched this video...
memirandawong 1 year ago
you just saved me from failing my statics test. thank you!!!
bigmosofly 1 year ago
I didn't quite get the cross product for the past 7 years and I managed to understand it in just 10 mins of this video.... Great job!
nilatstc 1 year ago
Excellent. Exactly what I was looking for.
beastlt12 1 year ago
dude fyi that is a pro hand :)
VulcanSpirit 1 year ago
By far the easiest version of the right hand rule I have seen.
kmiller1985 2 years ago 19
wat if i dont have any fingers?
lseateal 2 years ago 37
try to get some helping hand then.
paskavatta 2 years ago 3
@lseateal use somebody elses
ichinarukurumaki 1 year ago
@ichinarukurumaki
but im not allowed to use touch or talk to the people around me during a test! and i cant bring a friend in with me... i guess im destined to fail at any exam with cross products... : (
lseateal 1 year ago
@lseateal put on gloves.
nico2panama 10 months ago
@lseateal then how did you type this comment?
bartcase 9 months ago
@lseateal how did you type this comment then
hashmat187 8 months ago
@lseateal
lol I don't have any fingers either.
KimJong7hrill 3 months ago
@lseateal I guess it is not very difficult to imagine it
DasGewitter83 2 months ago
@lseateal you should imagine fingers and then work with it
SuperThegreat007 1 month ago
Thanks so much! Great help this :D
lastshadowmonkeys 2 years ago
I posted a quick example of how Cross Products are used in engineering. Hope you enjoy! Thanks for your videos Sal,
TheMrHandyMan 2 years ago
thank you, you have the best video that explains what a product rule is.
jjdc1 2 years ago
very lucid explanation, thanks!
ose90 2 years ago 2
that was very concise..
i'm learning this prior to my fall class because im afraid it'll be too difficult.
im sure i'll do great with your vids, in addition to MIT's OCW.
by the way,
you achieved and did so many great things in life,
congrats!
Ren520 2 years ago 3
Alternate method is to find the determinant - assume vector x = (a,b,c)T, y = (d,e,f)T, then the cross product of x and y is the determinant of the 3x3 matrix:
i j k
a b c
d e f
Obviously the cross is given by (i,j,k)T
hylianloach 2 years ago 3
outstanding
crashonthehumble 2 years ago
Wow!
SteveTheCart 2 years ago
Thank you so much. This was extremely helpful. Especially the right hand rule. God bless you. =)
cuzoma7 3 years ago 2
Thank you for all of these videos.
Eastyles 3 years ago 2
That was very clear, especially the part about the right hand rule.
Barnekkid 3 years ago 2
You should give yourself more credit with your artistic abilities; your work is really good.
brco2003 3 years ago 4
woohoo! First view, first comment!
This will help me in vectors since this is one of the stuff I will have to learn next year. Thanks a lot
GoldAK47 3 years ago 3