RESONANCE EFFECTS FOR EVERYONE TO SHARE test 12

[ssslawek]

I know that this is an old video and by now you are probably power your car with resonating coils but you should put the coils close together or on top of each other, so they would couple magnetically and not only electrically. But you might know it by now. thanks.

[Levolek]

I think problem is that you use rectangle signal input instead of sinewave. And digital multimeters can measure correct only sinewave signals... Please retry to do the same experiment but with sinewave input signal. Good luck. Oleksiy. orgonlab@cable.netlux.org

[halosux4life]

GIBBERISH me no speek ur language.

[tliff]

I was almoust scared, when you followed naked wires by your finger ;>

[ambocd]

the oscilloscope should be connected across the siganl generator to accuarately measure the input voltage. onother thing, the signal gen should have a setting for the output amplitude. so if you are sending squarewave and you know the amplitude and freq, you can calculate the rms volatge. then measure the current from the signal gen. the power input can be calculated as well.

[morpher44]

yeah I think the flaw is that your resistance is NOT 10 ohms on the input. You need to use Kirchhoff's circuit laws for the entire circuit.

[vretian]

You need to up your signal via car coil high voltage dc pulse is needed to enlarge resonance range. i have found that distance dose effect Aeter resonance current levels on the secondary coil which should be made of a sheald of aluminium flashing with a wire lead to a full bridge rectifier. Connect secondary lead to AC side, only 1 leg. DC side normaly to a polarized cap. when pulsing the whole thing you should be able to ge a fast charge into the cap.Use 2- 200v 220uf. good luck! VLADRXSCI

[prototype9000]

the resistor have a 5% tolerance

[projectmagnet]

At series resonance the voltage across the resister should drop or dip, and voltage across the cap & coils should peak. Current here now = E/R on the resister. Now use that current and multiply by the voltage comming out of the generator to get the total power. Next explore "impedence" Xc and Xl to get more accuracy, it will be a little different.

[projectmagnet]

Luc I may have that backwards, better review my resonant circuits. Parallel resonance is what I describbed. Series is the opposite, highest current at resonance. Current will peak on the resister, but the calculation is the same for power. P = E x I.

[projectmagnet]

Luc, the input power needs to be measured across all the devices not just the resister in series which only burns up a little. Check out measuring power in series circuits. Use the resister to find current through all the coils, now multiply current x voltage from the generator, it should come out higher.

[smokyatgroups]

The scope shows a sinewave cause the many additional odd harmonics in the square wave are not reaching the 10 ohm resistor, likely due to filter effect. The RMS value of the Gen's applied voltage if square wave is not the same as a sine wave.

Sine wave 0.35355 of peak to peak value whereas square wave is 0.5 of peak to peak.

Gen's applied sig should be sinewave, also to be measured across BNC connector preferably at load resonance where applied volts and current are in phase (Cos = 1).

[Drevtoobe]

Yes you are correct about using a sine wave instead of a square wave. When looking for resonance, the whole point is to use a single pure frequency (sine wave) because you might be thrown off by all of the harmonics in a square wave.

A point of information Luc: The signal generator has it's own isolation transformer inside it. Just about any piece of lab equipment will. To make your life safer you should get rid of the external transformer and get a new 3-prong plug for the signal generator

[minde4000]

Could you also measure input/output vs number of primary coils connected. I wonder if more pri coils draw more amps.

[batteryphil]

have also calculted the resistance of you caps and diodes? i am no expert by no means but even caps and diods have resistance.

[crob227]

does you signal generator use voltage?? great experimenting by the way im just trying to wrap my head around it....

[gotoluc]

Dear MRH2O2,

I am asking for help here on the correct way to measure. I have said so many times that electronics is not my field of work and I need help to do this right. Your explanation is not clear enough. I need it explained in plain English... like example: put scope prob A across SG and probe B across input resistor, then take RMS voltage reading of probe A and multiply by probe B RMS voltage, then divide by resistor value and so on and so on to get to watts input.

Luc

[Drevtoobe]

Luc, what you measured was four resistors dissipating power separately. You simply add the power of the first resistor to the power from the three resistors connected to the pick-up coils to get the total measured power burning in the circuit. This is essentially the same as the power the signal generator was putting out into this particular load setup at the output BNC connector. There is no special relationship between the three resistors vs. the single resistor.

[Drevtoobe]

I think what you were really trying to do was to compare the signal generator output power to the power you could measure coming from the coil resistors to see if there was something worth noting.

To do this you simply measure the current at the BNC connector using the 1-ohm resistor, and the voltage at the output side of the 1-ohm resistor using both channels of your scope at the same time. It's a reactive load also, and you have to factor in the phase angle between the volt and the current.

[Drevtoobe]

Just to make it more clear for you (I hope), I assume that you can get the RMS current from your scope channel A across the 1-ohm resistor. You can also get the RMS voltage from scope channel B.

If you look at two sine waves on your scope do you know how to measure the phase angle between them? Assuming you get the phase angle can you calculate the cosine? People in the forum can help you with that if you need it.

Finally the power is Vrms x Irms x Cosine(angle).

[altgenesis123]

@gotoluc You didn't measure the signal generator voltage, which I bet is more than 7.5 volts peak to peak or 3.75 volts RMS. Current through the resistor is 0.385 volts / 10 = 38.5 ma. Power across the resistor is .0148 W.

Current is the same throughout a series circuit. Power from the generator is 3.75 volts x 38.5 ma = 0.15 watts, exactly what you get out. Power out = power in, if you have 100 % efficiency. No power multiplier here. Sorry.

[MRH2O2]

@gotoluc

Sorry, but you can not measure across the 10 ohm and tell anything about input. You need to measure the voltage at the generator output (rms) and multiply that by the current going through the 10 ohm. Your calc is wrong the way you are doing it.

[gotoluc]

Hi InventorGadget,

originally I was going to use the small 1,000uf cap but I realized that many would say that cap is not large enough to clean the DC pulses and therefor claim my output voltages are incorrect. By adding these that argument has not come up. So you don't need these Large caps!.. unless you are trying to satisfy the measurement team.

Luc

[InventorGadget]

I am really happy of the results! :D

I like the approach with the same type of resistors/caps/coils everywhere, make's it really easy to replicate ans so on..

One question, why do you have the diode connected to a smaller cap, and then connected to the big cap?

Can one not make the diode connection straight on the big cap?

[gotoluc]

Hi marthale7,

yes I would agree! real easy to loop... but let's see if others can come up with something I maybe overlooking before we conclude this is 10X out from in.

Luc

[marthale7]

If you are getting 10X out, then looping should not be a problem, great video.

[tonysam11290]

Amazing videp gotoluc! You have me addicted to your videos and will hopefully be buying a signal generator soon to carry out these experiments.  Keep up the good work!

[gotoluc]

Hi tonysam11290,

get a used one for cheap on eBay since very soon we will not need it. Or just wait a week or two and we will provide a complete circuit.

Thanks for your positive comment.

Luc