Added: 3 years ago
From: willdabeast6
Views: 20,143
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  • big thanks from germany! ;-)

  • WOW GO SLOW! DAMN! you said you would but you went way fast and now i need to fix my cube again!

  • i never get parity thats on anyvids and it sucks

  • the second edge parity algorithem is X is the very inside layer: 2rx 2b 2u lx 2u r'x2urx 2u f2 rx f2 l'x 2b 2rx

    PLEASE THUMBS UP!!!

  • U ROCK WILDABEAST6 !!!!!!

    i can solve all my cubes and all the credit goes to you!!

    ur videos rock :D

    

  • post the fucking algorithm for last one

  • u started goin frickin speed racer on meth for the second parity

  • you go way to fast

  • the others only have one... but this has three... because it is a beast. lol

  • what if it's not a checkerboard?! (on the last 4 edges)

  • i love your tutorials

    there great thanks for the help

    i subscribed and so should everyone else

    thumbs up

  • 2:15 for last 2 edges.

  • 7:30 -- thats not very slow... thats way 2 fast. also, you can combine algorithm #1 and #3 and that will solve algorithm #2.

  • their are more paritys

  • whys this the last 4 edges? its just the last 2 that are difficult

  • "the 7 is a beast, and you need to be a beast, to solve" LOL

  • Got one for christmas, this vid helped me out.

    I worked out myself how to get to parity, and you got me past that. You've earned my sub, 5 star and fave!

  • im getting one for christmas. :D

  • what i will do is solve the 3 middle edges then the outer edges

  • v-cube blacks r now a collectors item :D

  • really?

  • yea the v-cube company aren't  selling them anymore :DDD

  • @willdabeast6 yuupppp

  • @d12ckool - I doubt they are, I just bought one last week...

    @wildabeast6, I've never had a parity error like the ones you show in this vid (which are the same ones from every youtube 7x7 vid) but when I solve my last 2 edges, I end up with 10 finished edges, and 1 or 2 pieces rotated perfectly onto the other side - as in I have 2 collums, BR-BR-BR-BR-YG and YG-YG-YG-YG-BR, how would you fix this?

  • nope, they sell black v-cubes again.

  • @d12ckool

    I have a Black one...

  • Thanks it still wouldn't work properly but then i re watched the video and found i had done something wrong when i had the last edges

  • What if you don't have any checkerboards in the last 4 edges

  • then you can't do the checkerboard shortcut. you just have to piece together each edge.

  • excellent tutorial help me a lot. i loved the way you talked. =)

  • why did you get a black v-cube?

  • because all my other puzzles are black

  • That algo is the same as te 4x4x4 edge parity algo! Yesz!

  • "YOU LUBED THE CUBE!"

  • still trying to memorize that damn alg, once I got that nailed I'm a beast lol. cheers mate!

  • where can i get the V-cube 7 thats black like yours? i bought one and its a white v-cube 7. i like the black better since it reminds me of a regular rubik's cube

  • you can just order it from V-cube's website. They give you the option of which colour you want.

  • You go to "V-Cube More" on the products menu. I personally like the white better. The black side compliments all the colors on the cube.

  • thanks now i can solve all the rubiks cubes i got stuck on the last four edges but then i found how to do it

  • no problem :D

  • i do edges diffrently and there is more parity to that way and no body explains it on youtube.

  • the genius edge that is always right

  • ur cool cuz u got the black set

  • Cool! A black one!

  • I can't do the stupid edge partity because when you go SLOW you go FAST.

  • well the 7x7 is advanced and I just assume you know of the parity algorithm from the 4x4 or 5x5

  • Yeah I figured it out. I'm doing the 20x20x20 soon.

  • haha tell me how that goes

  • Parity is gonna be like hell.

  • lol it's still the same algs, just on a larger scale

  • is there even any parity on it. because i solved mine like 3 times and there was none

  • 7 is an odd number which means there is no even parity. only even numbered cubes can have even parity

  • damn i solved mine using a different method and with my method it is possible to have permutation parity (well kinda )

  • if u only have 4 edges left, and u start solving the middle 3, wont u end up ruining one of the already completed edges? like 4 left, u get the 3, u need to put it somewhere but there is no where to store it.

    The way i do it is i solve a 3x1 with a wing instead of the middle 3 and then use a switching algorithm for each of the last 2

  • sweet tutorial...

  • those stickers look oddly placed

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