I have a question. Say you get tested 2 times. Intuitively, I would think the probability of, say, being positive and having it would increase substantially. But when I do the math by this same prob. tree method, I end up getting the same probabilities. What is the correct way of doing this? Or do the probabilities just not change no matter how many tests?
you need to start with 67/33 rather than 10/90 and follow same steps you increase the probability from 67% to 97.4% you have the disease if you test positive twice in a row!!.
I just wish i had seen this before. I was over the formula for quite some time without understanding it. This is by far the best method to do it, and its how I did it. Thanks for posting, this will help a lot of people. For anyone who wants to go even further, I suggest to investigate on Bayesian Networks (things get really complex down there).
explanation is for a basic math college math class, think artists journalists etc., not a statistics course. Hence, terminology of statistics is not strictly employed, but rather the way a newspaper or lawyer would speak of them.
It would be nicer if the terminology was a bit more strict. The term "accuracy" in this context is ambiguous at best (personally I would define accuracy as the proportion of true results ie. test result false in those without disease, test result true with disease). Sensitivity might have been a more appropriate term. (Although I do acknowledge that the terminology can get in the way of the basic principles)
It's a fantastic explanation of the principles involved nonetheless.
@shameelfaraz Because it's 92% of the 10% that have it. So take 10% of the population, then take 92% of that small group. e.g. population of 1,000,000 people, take 10%, that's 100,000 who have the disease. Then of those, take 92%, which is 92,000 who get detected (population x .10 x .92) , which leaves 8000 who don't get detected (pop x .10 * .08).
Thank you a million times for explaining so simply. I have been going throw books and some other youtube videos and I still didn't understand the Bayes theorem.
Your video helped me so much, and now I fully understand it.
Thank you, great video!
majorendre 1 month ago
thanx
magomah1 3 months ago
I have a question. Say you get tested 2 times. Intuitively, I would think the probability of, say, being positive and having it would increase substantially. But when I do the math by this same prob. tree method, I end up getting the same probabilities. What is the correct way of doing this? Or do the probabilities just not change no matter how many tests?
wangstick 4 months ago
@wangstick
you need to start with 67/33 rather than 10/90 and follow same steps you increase the probability from 67% to 97.4% you have the disease if you test positive twice in a row!!.
1960sadm 4 months ago
I just wish i had seen this before. I was over the formula for quite some time without understanding it. This is by far the best method to do it, and its how I did it. Thanks for posting, this will help a lot of people. For anyone who wants to go even further, I suggest to investigate on Bayesian Networks (things get really complex down there).
Khullah 4 months ago
you tested negative, what is the probability of you not having the disease: 0.914
nabecaydim 4 months ago
Comment removed
duffahtolla 4 months ago
This has been flagged as spam show
@nabecaydim Tested negative, chance of no disease: .855/(.855+.008) = .9907
duffahtolla 4 months ago
thank you
hicelina 4 months ago
Thank you so much for explaining this intuitively! Now I actually understand how to use it.
mastersgta1 5 months ago
great help! :D
Emjhey12 7 months ago
explanation is for a basic math college math class, think artists journalists etc., not a statistics course. Hence, terminology of statistics is not strictly employed, but rather the way a newspaper or lawyer would speak of them.
profribasmat217 9 months ago
It would be nicer if the terminology was a bit more strict. The term "accuracy" in this context is ambiguous at best (personally I would define accuracy as the proportion of true results ie. test result false in those without disease, test result true with disease). Sensitivity might have been a more appropriate term. (Although I do acknowledge that the terminology can get in the way of the basic principles)
It's a fantastic explanation of the principles involved nonetheless.
sweetburlap 9 months ago
why did we multiply .92 and .08 by .10 ?
shameelfaraz 9 months ago
@shameelfaraz Because it's 92% of the 10% that have it. So take 10% of the population, then take 92% of that small group. e.g. population of 1,000,000 people, take 10%, that's 100,000 who have the disease. Then of those, take 92%, which is 92,000 who get detected (population x .10 x .92) , which leaves 8000 who don't get detected (pop x .10 * .08).
danielearwicker 3 months ago
Wonderful explanation! Thank you = )
evelyn273 11 months ago
Very good video! I also like to write out the extensive form to solve conditional probability problems. Thanks for posting.
graw81 1 year ago
Thank you so much! I get it. I have been so lost for so long. I appreciate you taking the time to upload this for all of us!
WyndiFosh 1 year ago
Dear Sir,
Thank you a million times for explaining so simply. I have been going throw books and some other youtube videos and I still didn't understand the Bayes theorem.
Your video helped me so much, and now I fully understand it.
THANKS THANKS
kujta55 1 year ago
Thank you---I wish my prof. at U of Chicago made things this simple!!!
iym666 1 year ago
very nice; very innovative and precise. Excellent.
myutbest 1 year ago
very nice; with out talking about conditional explicitly; very innovative and precise. Kudos to you.
myutbest 1 year ago
nicely explained cheers
Silveralex32 1 year ago
Thanks!!! Very helpful!
isaiasperez 1 year ago
Wow, that helped a lot. Thanks.
stoicblade69 1 year ago
wunderful explanation
amin9846 1 year ago
Thanks for posting.
thenetaficionado2 1 year ago
EXCELLENT!!
twalsh90 1 year ago
Thank you, very clear and easy to understand, even for a novice such as myself.
jondesbrow 2 years ago