Added: 3 years ago
From: khanacademy
Views: 24,728
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  • Great tutorials! Very clear!

    what if we assume that area of surface of fluid (sof) is larger than area of the hole by a factor of k? the velocity of the fluid coming out of the hole will then vary with time. I tried figuring out the velocity as a function of time and i got v = k sqrt[(2k^2gh(t))/(k - 1)] where h is the height of the sof wrt the hole... and then i tried solving for h(t) by setting up (dh/dt)^2 = (2gh(t))/(k^2 - 1) (I hope thats right)... Can someone pls help me solve this?

  • thankyou very much ,concepts got cleared as easily as fluids flow :P

  • 2 hours not wasted thank you my friend

  • Thank you so much for these videos! They are much easier to understand compared to lecture notes and you make it really simplified.

  • thnk you sooooooooooo much

  • These videos are so helpful, and could you please continue on with hydraulic grade line and energy grade line concept? Thanks

  • the 1 dislike is someone who is sad that its ending.

  • this video can make me understand more my doctor. so i rely thank you

  • Thank you!

  • The one person who dislikes this video is CRAZY!!! Really useful video. Thankk you for uploading these videos. God bless you!!

  • an amazing review for my fluids text tomorrow, thank you!

  • Thanks for the fluid videos. It would have been nice if you did some manometer problems.

  • Sal's favorite phrase isn't "intuition" or "intuitive". It is "I don't know", which he says when he is making up numbers.

  • thanks for ALL the fluid videos :)

    they rerally helped. :)

  • thank you so much for the videos!! ur a great teacher

  • And thanks again :-)

  • From the master himself...

  • shukrran xhezijen ja sadijk :)

  • Thank you for the fluid videos! I watched them all!

  • well taught.

  • Thanks for the Fluids Videos!

  • You presented this very well.

  • Thank you so much, i really enjoy your videos, Thank you Khan, Shukran Akhi

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