@hodege1 On this one I think they are in parallel with each having it's own dropping resistor. I recently made a very cool flashlight (don't think I've posted it yet) with 35 led's on it! On that one I have them in series and parallel. I used five AAA batteries so I ran two rated at 3.2 to 3.5v in series and each set of two were all in parallel for power :) Look forward to me posting that one soon!@ :)
Just add two 100k restorers to the two data lines on the USB hub then bridge them to the positive lead and it would foul your device. The color band is brown, black, yellow, and gold
Also i dont think you can charge an iphone directly, because If i am not mistaken, an iphone USB charger sends a digital signal on the USB bus to indicate to the iphone that a genuine charger has been plugged in. You need this interface IC.
Also, i know some motorola phones require 5.5V instead of 5V with a standalone charger.
@THEtechknight Not sure about the i-phone 4 but you can charge the i-phone directly, did some research on it. the trick is to put a certain amount of resistance on the two data pins to show a certain voltage that the phone expects to see. Just search MintyBoost or LadyAda dot Net Pretty neat stuff. Thought about buying one of her kits but kind of fun doing your own thing! She has some other cool kits though!
@mikie2501 I knew it was something, I just could not remember what, because i researched this stuff years ago because of similar problems with other phones.
ok. You cant effectively parallel batteries unless the batteries are of equal charge. Otherwise, the greater battery will attempt to charge a lesser battery to balance the charge, even though they are NOT rechargeable (could be a bad outcome).
the power sources need isolated via diode. Each positive terminal of each battery needs its own diode. The diodes also need to be of low voltage drops. such as a shottkey. This way each battery cannot interfere with one another.
suprised you didnt use a switching regulator, with the linear regulator you are wasting almost half of your power as heat, if you used a switching regulator you would only lose maybe 15-25% as heat, much more efficient and all you need is a small inductor and a slightly larger capacitor
@Kingratass To be honest it just plain didn't occur to me, heh. I think the main thing was that the regulators I have were free after a bit of de-soldering, hehe. I'll have to look through my junk pile and see if I can find a switcher ...though I saw some from china on feeebay, like 10 for 10 bucks with free shipping or something.. (thinking future projects, hehe.) ...what does the inductor do in the circuit? ...I"ve seen some switchers that say they have the capacitor built in.
@mikie2501 free is always good if you are just building something to make it work/try out, as far as the inductor most switching regulators (dc-dc step down) are going to be bucking regulators, the inductor helps keep the switching ripple out of the rest of the circuit, inductor/small cap is more effective vs a large capacitor, check out some data sheets for examples of 5v power supplies, there are many out there, if you get a decent reg and the right inductor you could hit 90% efficiency easily
stupid idea mike , but it could prove to be a good one ...build another one from scratch , you know how to get it in the box and all , and test it out as you go , I bet you will find the mistake in the rebuild , then just fix the first one , and I will buy it , that seems like something so handy to have !
Mikie, you didn't breadboard first before building it. Not all LED's and resistors are the same. How many times can two parallel 9 volt batteries charge a cell phone?
My guess is once. Good luck debugging it. Enjoyed the video.
@hanky97007 Yeah, kicking myself a bit, heh. Breadboard sitting at my elbow too! lol. Turns out I had misplaced the power leads on 3 of them and put them on the output of the regulator instead of the input. 4 volts makes a big difference! lol. Oh, somehow I killed one of the leds while 'fixing' it. Now I'm trying to add a bit of resistor mess to put phantom voltage on the two middle pins to make the iphone charge. We shall see... heh.
is your leds in a parallel or series circuit
hodege1 4 weeks ago
@hodege1 On this one I think they are in parallel with each having it's own dropping resistor. I recently made a very cool flashlight (don't think I've posted it yet) with 35 led's on it! On that one I have them in series and parallel. I used five AAA batteries so I ran two rated at 3.2 to 3.5v in series and each set of two were all in parallel for power :) Look forward to me posting that one soon!@ :)
mikie2501 4 weeks ago
Brandon 14872 is right thats all you need to do.
Baseballt97 1 month ago
i know how to charge a iPhone 4 with you're charger, place a 100 ohm resistor between the information lines on the usb plug
brandon14872 3 months ago
Just add two 100k restorers to the two data lines on the USB hub then bridge them to the positive lead and it would foul your device. The color band is brown, black, yellow, and gold
jooel33 3 months ago
if you use rechargeable 9v batteries, you CAN parallel them directly together as long as they are discharged/recharged together in parallel :-)
THEtechknight 4 months ago
Also i dont think you can charge an iphone directly, because If i am not mistaken, an iphone USB charger sends a digital signal on the USB bus to indicate to the iphone that a genuine charger has been plugged in. You need this interface IC.
Also, i know some motorola phones require 5.5V instead of 5V with a standalone charger.
THEtechknight 4 months ago
@THEtechknight Not sure about the i-phone 4 but you can charge the i-phone directly, did some research on it. the trick is to put a certain amount of resistance on the two data pins to show a certain voltage that the phone expects to see. Just search MintyBoost or LadyAda dot Net Pretty neat stuff. Thought about buying one of her kits but kind of fun doing your own thing! She has some other cool kits though!
mikie2501 4 months ago
@mikie2501 I knew it was something, I just could not remember what, because i researched this stuff years ago because of similar problems with other phones.
THEtechknight 4 months ago
ok. You cant effectively parallel batteries unless the batteries are of equal charge. Otherwise, the greater battery will attempt to charge a lesser battery to balance the charge, even though they are NOT rechargeable (could be a bad outcome).
the power sources need isolated via diode. Each positive terminal of each battery needs its own diode. The diodes also need to be of low voltage drops. such as a shottkey. This way each battery cannot interfere with one another.
THEtechknight 4 months ago
suprised you didnt use a switching regulator, with the linear regulator you are wasting almost half of your power as heat, if you used a switching regulator you would only lose maybe 15-25% as heat, much more efficient and all you need is a small inductor and a slightly larger capacitor
Kingratass 4 months ago
@Kingratass To be honest it just plain didn't occur to me, heh. I think the main thing was that the regulators I have were free after a bit of de-soldering, hehe. I'll have to look through my junk pile and see if I can find a switcher ...though I saw some from china on feeebay, like 10 for 10 bucks with free shipping or something.. (thinking future projects, hehe.) ...what does the inductor do in the circuit? ...I"ve seen some switchers that say they have the capacitor built in.
mikie2501 4 months ago
@mikie2501 free is always good if you are just building something to make it work/try out, as far as the inductor most switching regulators (dc-dc step down) are going to be bucking regulators, the inductor helps keep the switching ripple out of the rest of the circuit, inductor/small cap is more effective vs a large capacitor, check out some data sheets for examples of 5v power supplies, there are many out there, if you get a decent reg and the right inductor you could hit 90% efficiency easily
Kingratass 4 months ago
stupid idea mike , but it could prove to be a good one ...build another one from scratch , you know how to get it in the box and all , and test it out as you go , I bet you will find the mistake in the rebuild , then just fix the first one , and I will buy it , that seems like something so handy to have !
towrecker 4 months ago
Mikie, you didn't breadboard first before building it. Not all LED's and resistors are the same. How many times can two parallel 9 volt batteries charge a cell phone?
My guess is once. Good luck debugging it. Enjoyed the video.
Hank
hanky97007 4 months ago
@hanky97007 Yeah, kicking myself a bit, heh. Breadboard sitting at my elbow too! lol. Turns out I had misplaced the power leads on 3 of them and put them on the output of the regulator instead of the input. 4 volts makes a big difference! lol. Oh, somehow I killed one of the leds while 'fixing' it. Now I'm trying to add a bit of resistor mess to put phantom voltage on the two middle pins to make the iphone charge. We shall see... heh.
mikie2501 4 months ago