i understand that for example when your looking at getting "exactly one head" but what if your looking at bigger numbers like 120 when you don't have time to type out all of the possible outcomes on an exam. is here a formula that you can use to determine the total possible outcomes?
Thank you so much for posting this video!! I am in 6 th grade in 8th grade math unit, and we have been learning probability 2 hours a day for 1 week and I did not get any of it. Watching this 10 minute video I figured out everything. Thank u so much!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Could you also cover Negative Binomial, Geometric and Hypergeometric distributions? All sort of similar but not... and when to use them, etc.? THANKS! :)
Also... moment-generating functions are confusing... and Chebyshev's Theorem (vs. Empirical Rule & Z-Score)...
I dont know how you can come up with a probability for the free throws.
Just calculate how many throughs of a fair coin you need, in order that the difference in module between the percentage of occurence of a previously choosen side and teoretical value of 0.5 is smaller then 1%, with a probability higher then 99%......
Anyway, you would need more then 250.000 throughs....
shouldn't each shot have the same chance of getting a basket? is the probability of a 3rd shot really affected by the probability of the 1st shot? isn't that a "gambler's fallacy" as that guy said in the 1st video?
@greatestwhoeverlived Well, you are right in the fact that the 3 events are independant, but that is why he multiplied the probabilities (0.8 * 0.8 * 0.8) this shows that the events are independant :)
yes it is correct :D if you think about it you have 1000 numbers from 0 (combinations of 3 zeros) to 999 (combinations of 3 nines). the fact is that you're counting numbers with just two or one digits as combinations of zeros and the numbers (for example, the number '67' is the combination of 0+6+7). so if you want to count the real numbers of combination with 3 digits you should count the numbers from 100 to 999, so it should be 900.
UberN3rdDillon answered your question correctly, however I just wanted to note that if you're finding combinations in which repetitions aren't permitted (i.e. not being able to use the same # more than once) then the answer would be 10 x 9 x 8 combinations or 720 ways of using the numbers 0 - 9.
that cheapo windows calc? --> there's an option to view the scientific calculator on it! -- gee that beats my MAC i'm using now :-(
BTW: Love your vids and help me a lot --- and I'm paying $1000 for my university subject via correspondence!!!! Why when I can learn from YouTube? These edu institutions are such a ripoff! But I need the paper...
Hey, if you go to 'view' on that calc you were using at the end of the video, you can select 'scientific' and it has everything you need. Good videos by the way, I am planning to watch the entire 'probability' series. Very clear explanations, unlike in most books.
Cool calculator move
Slackerx89 12 hours ago
probability of not getting head is very high
victim0001 3 months ago
i understand that for example when your looking at getting "exactly one head" but what if your looking at bigger numbers like 120 when you don't have time to type out all of the possible outcomes on an exam. is here a formula that you can use to determine the total possible outcomes?
eurojoe9 3 months ago
omg this just made sense!!!
benjtoa 6 months ago
If you have a TI calculator, you're allowed to download an emulator with the rom corresponding to your TI.
pattttttrick 7 months ago
I like orange juice
meschool 7 months ago
What's the probability of getting no tails when you flip an infinite number of times? Whoever can answer this gets a cookie. :)
iamtheplauge 7 months ago
@iamtheplauge
negative infinity
Franchan10 6 months ago
@iamtheplauge infinity over infinity? cuz its never ending.. you flip till like forever so there is forever results.. lol?
SyaukatTeh 6 months ago
@iamtheplauge answer: ∞/∞
..lololol
DarkLuster007 2 months ago
your writing is worse
absar45 8 months ago
lol that calculator
djjmria 8 months ago
Who are your parents????? Give them a big kiss for your Youtube family!!!!!!
MsNJohnson 8 months ago
Thank you so much for posting this video!! I am in 6 th grade in 8th grade math unit, and we have been learning probability 2 hours a day for 1 week and I did not get any of it. Watching this 10 minute video I figured out everything. Thank u so much!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Sporksrule120 9 months ago
Cheapo windows calculator!? bill gates wont be happy!
av733 9 months ago
Could you also cover Negative Binomial, Geometric and Hypergeometric distributions? All sort of similar but not... and when to use them, etc.? THANKS! :)
Also... moment-generating functions are confusing... and Chebyshev's Theorem (vs. Empirical Rule & Z-Score)...
StealTeal 9 months ago
oh my goodness look at all the parts to probability, this will be a long unit.
Shawn9081 10 months ago
I dont know how you can come up with a probability for the free throws.
Just calculate how many throughs of a fair coin you need, in order that the difference in module between the percentage of occurence of a previously choosen side and teoretical value of 0.5 is smaller then 1%, with a probability higher then 99%......
Anyway, you would need more then 250.000 throughs....
yeepieyeepiedoo 11 months ago
i have to send this video to our teacher to know the right of teaching
shyment3 1 year ago
I totally got lost in the middle of the video. i didnt like the explanation much. :/
TheUmairjafri 1 year ago
im in a statistics contest in our university. this would greatly help. thanks
TICOMMECA 1 year ago
Flip a coin with your girlfriend, you either get head or tail, you win either way!
doritoface123 1 year ago
who is the idiot who clicked on the dislike >:(
alabader741 1 year ago
@alabader741 probably bill gates
av733 9 months ago
shouldn't each shot have the same chance of getting a basket? is the probability of a 3rd shot really affected by the probability of the 1st shot? isn't that a "gambler's fallacy" as that guy said in the 1st video?
greatestwhoeverlived 1 year ago
@greatestwhoeverlived Well, you are right in the fact that the 3 events are independant, but that is why he multiplied the probabilities (0.8 * 0.8 * 0.8) this shows that the events are independant :)
Draconiandreaweaver 1 year ago
thanks for posting...its very helpful...
TheTayyab1 1 year ago
Just click "View" -> "Scientific" on the "el cheapo" calculator to get the exponent ;)
marceldupreez 1 year ago
thanks very much for clarifying that, my statistics teacher cant teach at all so you're a life saver ;)
the vid's very clear but i think you should put the probability of not getting a basket as B' (B-dash)
maksman93 1 year ago
You do have scientific calculator on windows. Check out the menus on the calculator. Windows doesn't suck that much lol.
mrvlhs 2 years ago 30
@mrvlhs why needs calculator when you can do that in your head.
trangnguyen1092 1 year ago
Its 8*9*10 = 720. See combinations and permutations (in this case its a permutation) to understand the concept of such problems
PinkZeppelin65 2 years ago
Comment removed
PinkZeppelin65 2 years ago
just a question how many compinations can numbers 0-9 make when they are used 3 times. like 548, 568, 395 Ect.
Angelrulesss 2 years ago 2
well you have three places and each place has 10 different options so that is 10*10*10 = 1000 different combos.
UberN3rdDillon 2 years ago 3
I'm not sure if that is correct because you didn't count for the different orders of the numbers.
But, like i said I'm not sure.
Budisawsome 2 years ago
yes it is correct :D if you think about it you have 1000 numbers from 0 (combinations of 3 zeros) to 999 (combinations of 3 nines). the fact is that you're counting numbers with just two or one digits as combinations of zeros and the numbers (for example, the number '67' is the combination of 0+6+7). so if you want to count the real numbers of combination with 3 digits you should count the numbers from 100 to 999, so it should be 900.
kuntakinte90 2 years ago
UberN3rdDillon answered your question correctly, however I just wanted to note that if you're finding combinations in which repetitions aren't permitted (i.e. not being able to use the same # more than once) then the answer would be 10 x 9 x 8 combinations or 720 ways of using the numbers 0 - 9.
JLack84 2 years ago
900 combinations
KidCollege 2 years ago
that cheapo windows calc? --> there's an option to view the scientific calculator on it! -- gee that beats my MAC i'm using now :-(
BTW: Love your vids and help me a lot --- and I'm paying $1000 for my university subject via correspondence!!!! Why when I can learn from YouTube? These edu institutions are such a ripoff! But I need the paper...
prsydaus 2 years ago 4
This has been flagged as spam show
haha your right
brentwoodbc 2 years ago
ahahhaha just like me
MissMinkyTheOriginal 2 years ago
Thanks Sal... I am reviewing prob and combinations for an exam and helps a lot...your work is inspiring...
mah927 2 years ago
awesome!
Nanumir 3 years ago
Hey, if you go to 'view' on that calc you were using at the end of the video, you can select 'scientific' and it has everything you need. Good videos by the way, I am planning to watch the entire 'probability' series. Very clear explanations, unlike in most books.
lascaux2123 3 years ago 17
@lascaux2123 and teachers
mukifurlan 1 year ago