Added: 3 years ago
From: vkiledj
Views: 24,508
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  • i think its better to pay 50$ monthly for your internet connection than to study for a thousand dollar fee xDDD

  • better explanation than my professor!! Thanks

  • Why does everyone keep restating the description of the video in their comments?

  • I Love The Video This clip illustrates how to use Gauss' Law to find the electric field outside and inside a conducting or hollow spherical charge. It Can Increase My Knowledge

  • Good, I like that you share this video, I wish success always This clip illustrates how to use Gauss' Law to find the electric field outside and inside a conducting or hollow spherical charge.

  • Nice Video This clip illustrates how to use Gauss' Law to find the electric field outside and inside a conducting or hollow spherical charge That You Share , So Very Nice Thanks You

  • I Really Like The Video This clip illustrates how to use Gauss' Law to find the electric field outside and inside a conducting or hollow spherical charge From Your

  • Your Video This clip illustrates how to use Gauss' Law to find the electric field outside and inside a conducting or hollow spherical charge Is Very Useful Sharing

  • gr8.... tHnX......... :))

  • Helps alot, applause :D

  • Dude this lecturer is amazing!!! Thanks :)

  • AWESOME!!!!!!!!!!!!!!!!!!!!!!!­!!!!! THANK YOU!

    

  • EXCELLENT PROFESSOR! I'M MEXICAN , HOPE I HAVE A TEACHER THAT EXPLAINS LIKE YOU DO HERE , I CAN UNDERSTAND YOU BETTER THAN MY PROFESSORS HERE!

  • your videos are really good sir....and it is very helpful for me to prepare for iit jee

  • Thanks a lot!! It has been very helpful!!! :D

  • great lecture

  • Thanx a bunch>>> I just aced my test because of him>> I was so lost yesterday and just watched his all videos till I fell asleep>>Today morning all made sense while I tried to check the exam review which I couldn't do yesterday>>> Thumbs up>>

  • i keep seeing e0 or permitivity of free space. what is that? i understand the electric field at a point r distance away from a charge q is =q/e0 but i read somewhere that this e0 is a constant? (physics cutnell\johnson) vol. 2 pg 555.)

  • @colinwar Yes, it "Makes things work out". It is a constant. I think your electric field equation is wrong - it involves a denominatior like 4*pi*e0*r, but I'm sure you've found that out by now

  • that guy works in my local pizza takeaway

  • For spherical coordinates dA = (r**2)*(sin[theta])*dtheta*dph­i in the r_hat direction.

  • why do i even pay $28000 a year for uni when I can learn all this on youtube? sometimes ever more efficiently than in uni lectures

    why

    thanks very much!

  • @hkpopfan4lif3 because you don't pay attention in uni?

  • @MattMcq99

    um, no

    

  • @hkpopfan4lif3 I couldn't agree more... But we pay that money now to make more later (with a degree). I don't like the process, but its the way it goes.

  • @hkpopfan4lif3 To get LAID boy!

  • @aliameen1000

    So that's where you parent's tuition goes....

    I kid

  • @hkpopfan4lif3 for that stupid piece of paper at the end that says you know it all :(

  • @hkpopfan4lif3 because you can get a degree =]

  • Very good explanation of Gauss' law. Thanks for sharing.

  • his accent makes the lecture much more interesting, lol

  • Comment removed

  • @thegreatgiginthesky i wish my university exam was as easy as yours if you were able to pass it from this lecture.

  • I wish this guy was my professor

  • the ugliest explaination i've ever seen...

  • Thank you so much. You've taught me this so much better than my own professor had.

  • You are a very talented teacher! I really appreciate simple and understandable summaries, like 6:09.

  • i like em

  • Comment removed

  • youtube has the best lectures!

  • Ok, i dont mean to sound like a tard. Ok, here is the question. Can you use the gauss law to propel a projectile forward? If im wrong let me know.

  • Not directly. The 'E' he solves for in this video is the Electric Field Strength. If you expose a charged object to this field it would feel a force.

    Force = charge * Electric Field Strength

    I don't think this would be a practical way of propelling a projectile though.

  • yes. Gauss' law gives you the strength of an electric field. Electric fields multiplied by the charge of the object in the field gives you the force upon the charged object. This is used to propel tiny charged particles extremely fast in particle accelerators.

  • yes, the law has such an impact on the physical world that it can propel projectiles

  • will you be posting physics notes on your site for purchase one day?

  • quite helpful. thank you :)

  • dA is a vector by definition. it comes out of the surface.

  • @vkiledj wait ! dA is a vector? i thought is a differential elemental surface where electric field is going thru the normal of.

  • why dA is a vector? I expected it to be a scalar

  • lol better than ucla physics prof

  • Great video, makes it all simple.

  • very good

  • very helpful 5+ stars

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