There's actually a formula wich is easier to use in that case (and similars).
It's: f(x) * f ' (x) = f(x)^n+1 / n+1
In words: When you got a function wich is a product, in wich one of its terms happens to be the derivative of the other term, then, the integral solution will be the f(x) to the n+1 power (being n its actual power (4 in this case) ), divided by n+1.
We re-write the integral as I: sin(x)^4 * cos(x) dx
The derivative of sin(x) is cos(x). Aply the form: sin^5(x) / 5 + c
@bmthnumber1 I'm sorry, at the end of my commentary I should have said: "The derivative of (sin(x))^4 (the term inside the parenthesis only -sinx-) is cos(x). Then, the criteria for using the formula is valid."
Wow, why are people being so negative, we are all human we make mistakes and learn from them, this guy is doing us a favour by providing helpful videos, if you don't like these then just leave the video and don't leave negative feedback, ungrateful people...
du/dx is a fraction... cant believe im posting this on youtube... but yeah... what he did is correct... execept when he wrote 2 times dx lol, good day
The facts: "u" is a _function_, and u(x) is the value of the function at point "x". So you can write u' as a derivative of function "u" for instance u=sin, u'=cos; u=id, u'=1; or you can write u'(x) or du(x)/dx, which means the _value_ of the derivative function u -- ie. u' -- at point 'x', 4example: u(x)=sin(x), u'(x)=cos(x); u(x)=x, u'(x)=1. So u' is a function and u'(x) is a number, needless to say there's a significant difference. So what about the du/dx, well it's meaningless.
dude have u ever studied math ??? du/dx means u derivate the function u by its variable x
its just a lineair operation. just think about partial derivation. ex if u do.. (dy/dx)*(dx/du)=(dy/du) now dont tell me that this isnt correct. nwayz, im not gonna argue anymore on this. have a nice day
Ok. d/dx can be an operator indeed, but not a fraction and we talk about analysis of real valed function, not operators anyway.
Furthermore 16/64=1/4, but not because of you can simplify the number 6. Correct answer, but not in the correct way.
I don't think we argue. You're right, but the analysis what you talk about is not correct theorytically, but correct formally. And we all know that the formal things are just secondary importance for the deep understanding.
How would you find the constant of integration if it were a definite integral??? (he said you coould in the video) I understood that the constant is unknown, an arbitrary value if you will.
Also, this question is way too easy.
Try finding the integral of
(x^2)/{(3+4x-4x^2)^3/2}
It took me 2 substutions and more than 20 lines of algebra....
hi! I have a question... Does anybody know how to find that stuff: you rotate a funktion from y-line and you rotate that volume from x-line again. What is the volume in the end???
u coulda explained the +C part-- u add +C becuase C is a variable standing for any number, in this case, because you are taking the indef. integral of the function, u do not know if there is a coefficient next to the x^0 power- which is C
Im learning math on youtube from now on, can't understand my stupid instructor anyways. I failed my first pre-calculus test, imma watch youtube and study. Area under the curve seems easy..but this, give me a week
lol that guy isn't very good integrating ... He put two dx in the same equation! but nice teaching though, its obvious that he is a highschool teacher .
now take the integral of sin^4(x) without cos(x) next to it and post a vid for me
xxcowslayerxxx 5 months ago
ala kang kayapan nimal!
rhobz2792 8 months ago
very much a helpful video, thank you very much.
colinwar 10 months ago
There's actually a formula wich is easier to use in that case (and similars).
It's: f(x) * f ' (x) = f(x)^n+1 / n+1
In words: When you got a function wich is a product, in wich one of its terms happens to be the derivative of the other term, then, the integral solution will be the f(x) to the n+1 power (being n its actual power (4 in this case) ), divided by n+1.
We re-write the integral as I: sin(x)^4 * cos(x) dx
The derivative of sin(x) is cos(x). Aply the form: sin^5(x) / 5 + c
Solved.
bmthnumber1 11 months ago
@bmthnumber1 I'm sorry, at the end of my commentary I should have said: "The derivative of (sin(x))^4 (the term inside the parenthesis only -sinx-) is cos(x). Then, the criteria for using the formula is valid."
bmthnumber1 11 months ago
hahahahahahahahahahahahahahahaha
IvanGangsta1 1 year ago
Wow, why are people being so negative, we are all human we make mistakes and learn from them, this guy is doing us a favour by providing helpful videos, if you don't like these then just leave the video and don't leave negative feedback, ungrateful people...
Yu2Kal 1 year ago
NERD
kinghustla187 2 years ago
really great idiot :D
birandkoray 2 years ago
the guy on the camera knows more than him
random19911004 3 years ago 6
he just show the common mistakes like that.. hehehe
chris5903 2 years ago
Lol, he's teaching calculus, but doesn't know what he's doing? du/dx = cos x dx?
wristrule 3 years ago
This comment has received too many negative votes show
Ummm...wait..isn't the derivative of sinx=-cosxdx?
netnplay 3 years ago
yup.
MPV839 3 years ago
i lied - derivative of sinx = cosx derivative of cosx = -sinx (opposite for anti-derivatives)
MPV839 3 years ago
Nicely done. Keep it up.
flipponzin24 3 years ago
d/dx however is an operator representing the derivative of a function of a variable "x".
nitish971 3 years ago
VERY IMPORTANT:-
"du" and "dx" are separate entities called "Differentials",.....so you CAN treat du/dx as the ratio of two numbers.
If u=f(x) is a differentiable function of x,
then du can be defined as du = f'(x)*dx.
If Simultaneously "u" is a function of another variable "y", then du = g'(y)*dy.
Considerable work is needed to show that these two definitions coincide.
nitish971 3 years ago 2
lol i love when he hits the microphone and whispers, "i didn't mean to do that"
ImaginaryHuman072889 3 years ago
hold up, did I do this right? LOL
juggy2008 3 years ago 5
SUPER EASY lol
this is like a basic u sub. problem (by the way I haven't seen the whole video at all yet)
haril007 4 years ago
dayı süper analatıon yaw:)
pasa6006 4 years ago
i love substitution
sh0cker13 4 years ago
integrate (f^n)*f' = (f^(n+1))/n+1
Anyway you cannot consider the du/dx as a fraction, use the substitution integral formula:
integrate f(x) dx = integrate f(g(t))*g'(t) dt.
csikjarudi 4 years ago
du/dx is a fraction... cant believe im posting this on youtube... but yeah... what he did is correct... execept when he wrote 2 times dx lol, good day
BBoyA2A 3 years ago
The facts: "u" is a _function_, and u(x) is the value of the function at point "x". So you can write u' as a derivative of function "u" for instance u=sin, u'=cos; u=id, u'=1; or you can write u'(x) or du(x)/dx, which means the _value_ of the derivative function u -- ie. u' -- at point 'x', 4example: u(x)=sin(x), u'(x)=cos(x); u(x)=x, u'(x)=1. So u' is a function and u'(x) is a number, needless to say there's a significant difference. So what about the du/dx, well it's meaningless.
csikjarudi 3 years ago
dude have u ever studied math ??? du/dx means u derivate the function u by its variable x
its just a lineair operation. just think about partial derivation. ex if u do.. (dy/dx)*(dx/du)=(dy/du) now dont tell me that this isnt correct. nwayz, im not gonna argue anymore on this. have a nice day
BBoyA2A 3 years ago
Ok. d/dx can be an operator indeed, but not a fraction and we talk about analysis of real valed function, not operators anyway.
Furthermore 16/64=1/4, but not because of you can simplify the number 6. Correct answer, but not in the correct way.
I don't think we argue. You're right, but the analysis what you talk about is not correct theorytically, but correct formally. And we all know that the formal things are just secondary importance for the deep understanding.
Have a nice day buddy.
csikjarudi 3 years ago
Look at 1:30 to 1:40...he got owned. "Times the derivative of what's inside, dx". More like times the derivative of what's inside, 1.
gamesguru 4 years ago
You always choose the easy ones.
SuperBrilliance 4 years ago
Wait, that answer is incorrect.
Its supposed to be - (sinx)^5 / 5 + C.
aswin1205 4 years ago
no it isnt
terminaterjohn 4 years ago
where did you get the negative sign lol
HappyCamper691 4 years ago
This is not a "rather complicated" integral. It is very simple. It looks like you had a bit of trouble with it yourself professor. lol
deathwishtomax 4 years ago
lol ownage
haril007 4 years ago
How would you find the constant of integration if it were a definite integral??? (he said you coould in the video) I understood that the constant is unknown, an arbitrary value if you will.
Also, this question is way too easy.
Try finding the integral of
(x^2)/{(3+4x-4x^2)^3/2}
It took me 2 substutions and more than 20 lines of algebra....
89tommyeflight89 4 years ago
Do a Laplace transformation, solve it in time space, and do an inverse Laplace transformation. :-)
operationcwal789789 3 years ago
Gracias me has ayudado mucho i like this video
gantz339 4 years ago
wow, integrals are like easy now
FlippinPin0y 4 years ago
I found this helpful, free teaching should be valued, great stuff!
zim01001 4 years ago
well i am 18 years old... In Greece we study integrals in the 3rd class of highschool, and i find that quite easy...
ligpgf 4 years ago
hi! I have a question... Does anybody know how to find that stuff: you rotate a funktion from y-line and you rotate that volume from x-line again. What is the volume in the end???
Lordbestami 4 years ago
what do you mean you think its easy... it is child's play...
11hani11 4 years ago
cheapass did not record in stereo mode again.
bkjoelover 4 years ago
I am Calculus College Teacher And I am only 22 years old , I think that this calculus is quite easy.
hanshv 4 years ago
Well, of course you think it's easy. Read the sentence you just wrote. -.-'
I'm only two months into Calculus, and I'm loving it so far. Keep up the good work, guys. =P
TheOnlyTyrael 4 years ago 3
lol his ass got pwned at 1:35.
bkjoelover 4 years ago
Yeah, that was weird. I'd redo it before uploading. :p
ultranordic 4 years ago
this guy is an idiot
seyedseyedi 4 years ago
hmm i never thought of that i was like maybe you can split the power 4 to sin^2 times sin^2 ----> then sin^2=1-cos^2...
Aloosh12 4 years ago
that's mathematically wrong.
xlynnduh 4 years ago
Look at this guy's awesome handwriting
badfutureuk 4 years ago
u coulda explained the +C part-- u add +C becuase C is a variable standing for any number, in this case, because you are taking the indef. integral of the function, u do not know if there is a coefficient next to the x^0 power- which is C
sweatshopboy 4 years ago
it's easy....
macchonk007 4 years ago
yeah man its so easy heh i remember back in the day learning that at high school going whaaaa lmao :P i love doing a degree in mathematics :D
RedBrain812 4 years ago
Have u even finished school.. n00b
Vaeth13 4 years ago
lol so true mate, though he's trying, so gotta give it to him
mturewicz 4 years ago
gd job..
zaith88 4 years ago
wow...
haquearsh1 4 years ago
EASY!!!!!!
Melan07 4 years ago
this is too easy:D
nosotrosde 4 years ago
i failed my first pre-calc test cuz i cant understand my dumb instructor, but this is good. Youtube math rocks!!
nas2k44 5 years ago
Im learning math on youtube from now on, can't understand my stupid instructor anyways. I failed my first pre-calculus test, imma watch youtube and study. Area under the curve seems easy..but this, give me a week
nas2k44 5 years ago
sad, he's making it way too complicated
Differentiated 5 years ago
Here's an easier way.
1)Take the sin/cos forget for the moment what is in the bracket, and find the integral.
2)what you have just found by what is differentiated inside the bracket.
3) put +C at the end!
PhilipGreen666 5 years ago
Far, FAR over complicated!!
PhilipGreen666 5 years ago
awesome, I understood his teachings
speedytheturtles 5 years ago
integrate e^(-x^2)
ssnatcherss 5 years ago
it's sqrt of pi
praky23k 5 years ago
lol that guy isn't very good integrating ... He put two dx in the same equation! but nice teaching though, its obvious that he is a highschool teacher .
barca7jr4 5 years ago
uhhh, he just did that perfectly, and neatly. what are you talking about?
he should do more interesting problems tho, this is too easy.
drcroc2 5 years ago
AMAZING!
olgis 5 years ago
dont want to learn on youtube.
b0000b 5 years ago