from the moment that I saw that you flipped the axes.... it was a turn off. Nobody teaches it like that in classes. So why teach people a method that will be foreign to them?
It still begins to exist at 0 to 1 ! Both limits start at 0 and ends at 1. Why in the world you are saying that it starts to exist at x=sqrt(y)? The same thing you could say that it started to exist at x=y and ceased to exist x=sqrt(y).
it\'s confusing. why would you flip the axes?
kVellarina 11 months ago
from the moment that I saw that you flipped the axes.... it was a turn off. Nobody teaches it like that in classes. So why teach people a method that will be foreign to them?
waspy89 11 months ago
it doesn't make any reasonable and logical sense. This is 5th video I'm watching
4:07 where does it begins to exist?
It still begins to exist at 0 to 1 ! Both limits start at 0 and ends at 1. Why in the world you are saying that it starts to exist at x=sqrt(y)? The same thing you could say that it started to exist at x=y and ceased to exist x=sqrt(y).
sandslash123 1 year ago
Comment removed
sandslash123 1 year ago