Gauss's Law and Co-axial Cables or Cylinders (part II)

[lasseviren1]

No, the E between r=a and r=b will be (lambda)/(2*pi*r) where lambda is the linear charge density of the inner wire and r is the distance from the center of the wire to the place you want to know the field.

[yudanielk]

This is a great video but I do have a question...

Since the electric field outside the coaxial cable is 0, does that mean that the electric field for the distance between a and b (a < r < b) is also 0?