awesome description instead of solving for the amps though you can use V i R think of it as a division symbol (V divided by i times R (equals V), but cover up the one you want to solve for, i = V divided by R and R = V divided by i)
In 2:16 you said you divide both sides by 6 ohms how does one know that it's to be divided by 6 ohms is is because it was initially 6 ohms already and can that method be used each time I x the number of Ohms is divide on both sides ?
I like this.
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rebelliouseoagj 1 year ago
when you summed number 2 ands relised 4 is double 2 shoulda saved your self some time and assumed a correct answer lol
Jamieduk999 1 year ago
V / i R
immytown 2 years ago
awesome description instead of solving for the amps though you can use V i R think of it as a division symbol (V divided by i times R (equals V), but cover up the one you want to solve for, i = V divided by R and R = V divided by i)
immytown 2 years ago
I just energized it with 12 volts and boom I got power.
HHOhybridBuilder 2 years ago
I realy don't know how this happened.
HHOhybridBuilder 2 years ago
good vid
TrojanHorseXX 2 years ago
sorry typo is it because *
Blackseed1978 3 years ago
In 2:16 you said you divide both sides by 6 ohms how does one know that it's to be divided by 6 ohms is is because it was initially 6 ohms already and can that method be used each time I x the number of Ohms is divide on both sides ?
Blackseed1978 3 years ago
You have V=IR
you want to rerarrange the formula to find 'I'
the opposite of multiplying is dividing, so to get rid of the 'I' on the right hand side, you divide it by 'I' (I in this case = 6)
You have to do the same to both sides of the equation, so the left hand side becomes V/I, or in this case 12/6
He divides the 6 by itself to give 1. multiplying by 1 wouldn't change the value for I since it has to be positive (can't have a -ive current).
hope that helps?
Oneill9293 2 years ago