Maths 911 - Grade 12: Calculus, log inequalities

[jdz205]

how would you do 1-0.75^x > 0.625 ???

[NeoXC]

I'm a bit confused here. You say the answer is between -2 and 5/2. So, I plug in a number between 0 and 0.5 into the original equation log[x(2x-1)] and come out with a negative answer. However, you cannot have an answer like log(-2) or any other negative number in your log. So, why are the values from 0 < x < 0.5 defined as true?

[NeoXC]

negative number inside the log* not negative answer

[eddystyle213]

thanx for the video.

it helps me a lot !!!