Added: 4 years ago
From: khanacademy
Views: 23,431
Sort by time | Sort by thread (beta)

Link to this comment:

Share to:
see all

All Comments (21)

Sign In or Sign Up now to post a comment!
  • I am very happy to see the vidoe Another example of projectile motion.after you give this

  • I Love The Video Another example of projectile motion It Can Increase My Knowledge

  • Steady I Really Like This Video Another example of projectile motion

  • i guess the one dislike was b/c someone misunderstood his video and bombed a test...

  • I almost cried laughing when you said...."My trusty calculator provided by windows", and just pulled it out.. xD

  • i got 1 question

    for example you throw a ball up at 10m/s

    at t=0, is v=0m/s (snce motion hasn't started yet

    or v = 10m/ss

  • @cheese0cake it's 10m/ss the moment it leaves your hand.

  • How fast did I throw up? LOLLL

  • I have a question: In a projectile motion (one motion), does the time for the object to travel from the starting point (y*0=0) to the highest point equal to the time for the object to travel from that highest point to the end y=0?

  • Comment removed

  • @achtpanz88 Yes it does.

  • I understand why final velocity is zero, but it always seems to me that initial velocity would also be zero, because the ball has not been thrown yet. What am I missing here?

  • thats because you have to throw against the pull of gravity. so basically you throw it at x m/s UP, which is your initial velocity, at the half-way mark, the velocity changes to x m/s DOWN, or -x m/s UP. From there on, the velocities start to cancel each other out, leaving you with 0.

  • ball throwing

  • gr8! i tried to solve it the other way i.e. by taking vi=0 nd taking vf=unknown nd i got the same answer 35m/s... thankyou! for giving such a gud aproach 2 dis prblm cuz wat v usually do is mug up the formulae nd aplly it but this is really get! after watchin ur videoes i started appretiating phy but nyway its too late nw.. i'm alredy prep 4 medical!! thanks a lot sal!

  • thanks so much for posting all these wonderful videos! they really do help me out a lot. i have always loved physics until this year where i had such a difficult time keeping up. i really wanted to enjoy it again so you are definitely being a real big help. i appreciate it. :)

  • Your vids r real helpful. Thankx for uploading.

  • He solved the problem without resorting to formulas. Since you knew the t = 3.5 secs and g = -10m/s^2... you know that v_i must be 35 because 35 - (1)10 - (1)10 - (1)10 - (1/2)10 = 0. Now that you have v_i and v_f, you just average the two and plug it in d = (v_a)(t). (you can average them simply because the velocity is linear and the acceleration is constant).

  • why cant we use the distance= (vf2-vi2)/2a?

Loading...
0 / 00Unsaved Playlist Return to active list
    1. Your queue is empty. Add videos to your queue using this button:
      or sign in to load a different list.
    Loading...Loading...Saving...
    • Clear all videos from this list
    • Learn more