@jamesrule1 You could do it that way but in this case it's not necessary. With this method of soling the problem, it's the ratio of one distance to the other that matters, and that ratio will be the same regardless of the units.
@OoOIvaNOoQ I know this probably isn't any help to you, but I dislike how he does this problem... The best way to do this certain problem [for me]is to set up two separate coulomb equations, and divide them by each other, which pretty much cancels out the q's [which are unknown anyway] and the constant 'k'... you'll get an equations like f1/f2=r1^2/r2^2..or in this case, .38N/f2=6mm^2/9mm^2, and solve for f2
@eklipz330 this is exactly what he does, but he skips the steps of actually writing the equations and dividing them by each other. The result is the same, as after the division you would end up with the exact ratio for F2, as F1/1.5^2. This is just a lot faster and easier to remember. It's good to know where it's coming from, but one you know and understand, you can solve directly.
You are cool, Mr. Owens. Thanks for guiding me through me essay, this is very informative. *bows down*
Panicatthebusstop 3 months ago
Comment removed
souzou1000 4 months ago
@souzou1000 "Fear leads to hatred, and hatred leads to the Dark Side." -Yoda
derekowens 4 months ago 4
@derekowens lol U got issues... why would i Fear physics loser???
souzou1000 4 months ago
@souzou1000 dumbass. can't you see a joke when its staring at you in the face
naruto2710 1 month ago
@naruto2710 Hahahahah I see ppl coming out from trash and talking shit on youtube!!! ppl like u will be ignored!!
souzou1000 1 month ago
@souzou1000 yh, thats why you replied
naruto2710 1 month ago
@derekowens But...but.... the dark side has cookies!!!
Panicatthebusstop 3 months ago 3
@souzou1000 they hate you too
Bruinboi16 3 weeks ago
I love you.
frostmonke 1 year ago
Why is it the "mm" not converted to METER??
jamesrule1 1 year ago
@jamesrule1 You could do it that way but in this case it's not necessary. With this method of soling the problem, it's the ratio of one distance to the other that matters, and that ratio will be the same regardless of the units.
derekowens 1 year ago
@derekowens thank you sir for the explanation
this is the first time I encounter Inverse Square Law.
jamesrule1 1 year ago
this was so helpful!
unicornguard 1 year ago
very nice !!!! keep it up
drbubble2 1 year ago
Very helpful!! Could you PLEASE do more inverse / inverse square proportion problems in Physics?
It would be amazingly helpful!!
bomberfun1 2 years ago
i don't understand how you can just divide by the factor^2 and find out the new force...HELP PLZ
OoOIvaNOoQ 2 years ago 2
@OoOIvaNOoQ I know this probably isn't any help to you, but I dislike how he does this problem... The best way to do this certain problem [for me]is to set up two separate coulomb equations, and divide them by each other, which pretty much cancels out the q's [which are unknown anyway] and the constant 'k'... you'll get an equations like f1/f2=r1^2/r2^2..or in this case, .38N/f2=6mm^2/9mm^2, and solve for f2
eklipz330 1 year ago
@eklipz330 this is exactly what he does, but he skips the steps of actually writing the equations and dividing them by each other. The result is the same, as after the division you would end up with the exact ratio for F2, as F1/1.5^2. This is just a lot faster and easier to remember. It's good to know where it's coming from, but one you know and understand, you can solve directly.
apollotm 1 year ago
amazing
prosk8er 2 years ago