Added: 3 years ago
From: patrickJMT
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  • you are 1000 times better than my math teacher?

  • In the 2nd example, could you do "6C10" instead of "10C6" ? Or would that not work out correctly?

  • @roswellhorn24 BRANDO!!!! studying for finals??

  • your dna needs to reserved

  • i'm having my major examinations in a week's time and i'm aiming to watch through all your videos by one week.

    OH, THE BURST OF KNOWLEDGE!

    oh! and thank you so much for these educational and informative videos. much appreciated! :)

  • Excellent.  Great word problems as well. Thank you.

  • ur freakin amazing

  • At 6:33 instead of cancelling all of the denominator outI did this and got the same answer. 4 goes into 8 twice giving me 2 and 3 goes into 9 3 times giving me 3. Then, I left the remaining 2 on the bottom and divided the numerator by the denominator. I got this: 10 x 3 x 2 x 7 / 2 giving me 210. Is this still correct?

  • What did you do @ 4:42 - 4:55??

    I get the point of doing it... but what's it called? o.O

  • @crishtta Oh.. I thought about it.. can you call that procedure "simplifying" too?

  • THANK YOU!!!

  • the total NUMER of combinations @ 0:08-0:54 :P

  • there is a new GRE coming out am i right? anyone know anything?

  • I know someone who's a DICK !

  • Lol... I guess Jackie Chan was right. There's no such thing as a bad student, only bad teacher which is why I turn to you, an AWESOME/EPIC/ STILL EPIC/ AMAZING teacher ;)

  • suppose you have 7 red balls and 5 blue balls how many ways can you pick 4 balls with any colour , is that a Combinations or a Permutations ?

  • thanks for the vid =p

  • Thank you so much :) This helped a whole lot!

  • Hello Patrick! I need some help and I was wondering if you could make a video on how to solve it.

    I have 50 euros and I want to spend all of it on exactly 10 books.

    The bookshop that I go to has books with pricetags of 21, 18, 16, 14, 13, 12, 10, 8, 6, 5, 4, 3 and 2 euros.

    I must spend all 50 euros and I must buy exactly 10 books! (maybe because my bookcase doesn't have more room or something :P)

    Could you make a video for solving this kind of problem?

    Thanks!

  • so basically combination is random and not specific and premutation is...??

  • what's your website address? i would rather hear your video than others.

  • thank you sooo much for this video! One poker player to another, though, it is inaccurate to say 'full house with 3 aces' in the poker example. The remaining 2 cards must be a pair in order to be a full house. Wouldn't you need to choose the number of pairs of the remaining 48? I think originally starting the example you said 3 aces with any two cards and later after solving you said this is the number of 'full house' combinations with 3 aces. Anyhow,I can thank you enough for the refresher!

  • u are truely helpful i am glad i have found ur videos the way u explain things is so clear to me i love it i wish every math professor was like you maybe we would understand it much better and it wouldn't be so difficult to get through also ur tone is not boring like most professors

  • I don't get it , I guess it's because I'm dumb. :/

  • i love you patrick. because of you, i see the world so much clearer

  • wow thanks a lot, really good examples, thanks a 99999! :)

  • Hey ,,, i loved your videos.. these are fantastic.. simple & yet impactful..its beed years since I ever saw this..really usefull...please keep of the good work //

  • Thank you for taking time out to teach others!!! I was struggling in my last college math class and this really helped me understand the permutation/combination formulas by hand! (Worked out without calc.) Will be coming back to see other videos!

  • Thank you so much. I've been stuck with this worksheet for about an hour now. As soon as I saw your videos I almost cried. You are better than my math teacher, it is like a 1 on 1 tutoring. Thank you so much, you've changed my life.

  • @WeLostAlpha glad it helped!

  • hey look a samuel adams commercial before i try to learn math!

  • @sunslap tasty!

  • i want you to know that even though you have a small amount of views on ur videos you are making a difference in just one persons life with your online lectures..... please keep up the good work man!!! Thanks.

  • @jvboy88i did not realize 17 million views was small. i will have to try harder.

  • @patrickJMT I think jvboy88 meant views per videos,not all views in totall.

  • really thx for this lesson was really understandable and i got it all thx alot even more since i got my exam tommorrow:p and to be honest i was giving up on it^^so i started watching youtube being bored:p

    Then i thaught lets just search up my lessons and i came up on this and i was like let's give it a shot. I was so happy i found this:D really thx and thumbs up for the help

    grtz from belgium

  • I have to say I never seen this in my life but my statistics class requires it, with your help I understand them enough to get me through.

  • thanks youtube biostatistics teacher hahaha ! i understand the permutations and combinations but a lil problem in "3 aces or sumting" but i'll repeat it until i understand everything.

    thank you so much ! tomorrow is my exam in this subject :D

  • do u have more examples that are like the last examples?

  • Hi Patrick,

    Thanks a lot for these videos, really helpful in my GMAT preps. I had a comment on the last problem that you discuss in this video. The answer to the problem is correct, but you happen to mention that these are full house combinations.I believe a full house is when you have 3 cards of the same type and 2 cards of the same type.

    In this case shouldn't the answer be 12 x 4C4 x 4C2 =288

    this is a combination of 3Aces,2Kings or 3Acess,2Queens etc until 3Aces, 2 2s

  • U ARE A LIFE SAVER!!!! Omg! I have a exam tomorrow and my professor jus sucks and this really helped a lot! Thanks!

  • What is the purpose of multiplying the demoninator by r!?

  • this is a probability question that my math teacher gave me..---- this is combination..ok

    11 persons have to be selected from 6 teachers, 4 parents and 9 students to attend a seminar. Find the number of ways to select them if the group must consist of

    (a) 2 teachers.

    (b) 3 teachers and 3 parents

    ------------------------------­------------------------------­-----------

    can u help me.. ^_^

  • 7 People are not poker fans

  • @1flhippy yes, remembering all that one has seen before is the hard part to me as well. there is just sooooo much we learn.

  • I've just started learning about combinations and at power sets I don't have clear about P(8) or P(7) if its must be like P(8)=8x7x6x5x4x3x2x1 or just 8,,,P(7) = =7x6x5x4x3x2x1 or 7.... which is the correct one????

  • tired of this adds before the video

  • @toichi1974 so stop watching

  • @patrickJMT Hello i would like to request you to make a video on permutation with repetition.....please help me to clear some of my doubt that i have in permutation

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  • Combinations of a full house with three aces:

    4C3 * 4 * 2 * 12 = 240

    Choose 3 aces out of four and choose 2 cards out of 4 times the number of remaining ranks deuces till kings =12)

    Right?

  • @haridarshana 4C3 * 4C2 * 12 = 240

    correction

  • Hi, a full house is a 5 card hand with three of kind and two of a kind. In this case you have three aces and two cards which might or might not be paired. So not all the soluations are full houses.

    Thanks for the video though. When I tried the problem for myself, I forgot to include the multiplication with 4C3.

  • thanks man!!!

  • i don't understand it! :(

  • you're awesome, thanks patrick!

  • very nicely balanced lecture this one is

  • Again, thank you! 6 days til my clep! With your help I coudl actually score! lol VERY helpful!

  • I got 451.2 without using your formulas. I did: (4*3*2*48*47)/5*4*3*2*1

  • very helpful indeed.. but I have a concern. Just like you said; someone who is not a "poker fan" or has never played poker before will not be able to answer such a question. What if it appeared in a standardized test or exam.. what could the person do?

  • @donloxy24 i can not imagine it would appear on a standardized test for that very reason; people have already thought of that i am sure. it is like if there was a question regarding chinese chess... i would do the only reasonable thing: guess, probably get it wrong, and move on.

  • @Darkdanz93 you and 800 other people want it : )

  • This is the Binomial expansion, Its linked with pascal's triangle

  • This is a good tutorial, but in the last problem, you're actually NOT finding the # of ways to make a "full house of aces." You're actually finding the # of ways to make a "three of a kind of aces." Some of ways are full houses, but most of them aren't.

  • i hereby recognize all of your effort

  • Comment removed

  • Thanks this is just what I needed for my finite math homework

  • i don't see a point in my teacher teaching anymore.

  • @d3m3nt3dang3l I doubled that too :)

  • 13,000 views n just 57 rating?? i think he deserves more than that !!

  • wow this is exactly what I needed for GRE tomorrow!! thank you so much! I feel so much better about it now!

  • Thank you very much !!

  • u r god damn genius !

  • thanks i had maa trouble widd that

  • thanks mate

  • You are AMAZING!!! Thx! :O)

  • Great video! It makes it so much easier in that you are a lefty- we can see as you write. Thanks!

  • OMG !!! thaaaaank u XD this totally helped me in my statistics homework !! YAY

  • i have a question :P

    how many hands of 13 cards containing 4 spades, 3 hearts, 3 diamonds and 3 clubs can be dealt from a 52- cards bridge deck?

  • Brilliant tutorial 10/5!

  • thanks :D

  • Great vid. But at the end is it really a full house? The way I see it is that those 2 cards can be different.

  • ok i dont get it! :(

  • One thing I don't get. If I were to choose 2 cards out of 48. There are 1128 different combinations (48*47/2). So with the three A's and those two cards there can't be 4512 ways to get a full house? But it's 4512 ways to get three A's and two other cards, which do not have to be a pair. Am I correct?

  • so where did er,, why did from the first ex. 5C2 = 5!/(5-2)!""2!"" where did that """two""" come from???

    well thank you! it was bunch of help!!!!!

  • formula is n!/r!(n-r)!.

    the 2! is r!

  • Appreciate this video. Taking an online elem statistics on undgrad level. There was a part in the book that got me stumped when it 5!/ 2!3! . I didnt know how to do the lower section of factoring out. The book gave an example but didnt explain. Understood your concept. Thanks and appreciate it!

    Vince from South Texas

    UT Brownsville

  • hi i'm thinkin of going to ut Austin. I want to know if you recommend that school. THANK YOU...

  • ut austin is great school.

    you can watch me tutor there every day... it will be like youtube live

  • for example number, where the question is 5C2 why is r=2?

  • because it is nCr , the problem is 5C2, thus n is 5 and r is 2

  • This is quite good. I can refer my high school students to this. Thank you.

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  • i dont get example 2, word problem. it could be permutation because if you pick an answer, you can't pick it again... right?

    help me please!

  • that's why it's without replacement

  • PErmutations = order does matter

    Combinations= order doesn't matter

    Thus in this question it doesn't matter what order you pick, it's asking you to just pick 6 questions. Doesn't have to be in order.

  • thank you

  • hey patrick, it might help people too if you explained the relationship between the combinations and the permutations.

    permutations = (# of combinations)x( r! )

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  • thanks mr.patrick!!:)

    i wish you were my brother!to teach me every time i dont get it..lol!!

  • my teachers way of teaching us, is for us to teach ourselves and frankly i really dont find tht helpful, but this video is so simple and well explained im excited... im actually teaching the class hehe THANK YOU!

  • one small poker thing:  you calculated being dealt pat trips, not trip aces and definitely not a full house. Check your math; you dont discount for the probability of being dealt KKK, QQQ, et cetera.

  • dude thanx a million

    u teached me everythin i needed to now...in less the amount of time it would take me teacher!

    seriously i think ur the best maths teacher there is

    i wish i had a good maths teacher who didnt have favorites like my math teacher

    its so annoyin cuz one of my classmates is really brill at maths and shes his fav student so he expects us to be as smart as her

    and he called me arrogant just cuz told him that this stuff is easy for our class so we should do a higher level

    thx dude

  • All of your videos are so helpful! Thanks so much!

  • Your not necessairly coount full houses.

    Your counting a triples though.

  • You saved me!

    I sat in 4 hours of classes this week and you explained EVERYTHING i needed to know in 10 mins!

    THANKS A BUNCH!

  • how come it isn't (52C3)*(48*2)??!?!

  • you should be my teacher ....my teacher says that she already passed math and its not her problem if were having trouble.

  • lol, what a bitch if she really said that : )

  • she is she resllky said that.....and that we shouldn't even be in that class lol

  • thank u so much =D

  • Hey. Thanks for your help. Many people told me that Statistics is easier than Calculus (since I'm taking both at the same time), but I felt the opposite. Could be wrong. Thanks again.

  • we had our lecture about this topic last week but i did not understand my teachers explanation! thanks for your help, it helps me a lot! hope you post more statistical video like chi-square..etc, tnx

  • in ex 3 you are not counting full houses. you counted hands like AAAJ2.

    Full houses will be 4C3 x 48 x 3 / 2

  • Thanks for this man, i wish you luck in your university

  • studying online is really effective... thanks for your video! I feel confident now for the exam tomorrow

  • best of luck on it

  • thank you. you're a really good teacher. however: a "full house" would only include AAA + KK or 88 or any other two card combination of similar denomination. In this problem, we're accounting for AAA + any other two cards....right? for instance, AAA + 5 and 2.

  • Lol, ur left handed. Nice

  • i have a problem; if you have a 52 card deck, and you chose 5 cards what is the probability of getting a pair out of the 5 cards.

  • ok so here you use the formula when each case will occur withe equal chance so its p(pair) #(E)/#(omega) where E- # of cases in E... and omega- #of all possible cases

    so your questioin answered- - p (pair) [(5 2)x(47 3)]/(52 2).... hope that helps, the top is 5 cards, a pair is 2 and multiply this by the 3 other cards that are not a pair or are random cards... and all that over the total cards and 2 which would be your pair, ... you use the combination thing,, where its (n r)

  • hi,

    this video is listed twice in the playlist; at no. 4 and no. 5

  • ops, thanks! i will delete one of them!

  • why it's no longer available?It was there months ago~Now I'm depressed~

  • what is wrong.. was my video not playing? it is still available!

  • great review, im gonna have an exam tomorrow on this :D

  • me too dammit

  • im the same as you jackferwarda :P i think i can handle it tho. Thanks m8 your an awesome teacher times well.. factorial!

  • which problem do you refer too? in some problems, the order (to me at least) clearly DOES NOT matter, so it does not seem at all counterintuitive.

    i mean, suppose you were picking 5 people to go on vacation with you; it does not matter if you pick people a, b, c, d, e in that order or e, d, c, b, a in that order... it still amounts to the exact same group!

  • am I alone in thinking that the phrase "the order does not matter" in questions like this is somewhat counterintuitive? Let me know your thoughts because evertime I see that in word problem like this, it throws me off.

  • hahhahahhaha, if you really wanted to, i suppose a picture could be arranged : )

  • I have a data exam for grade 12 university math and you have just become my hero (factorial factorial factorial)

  • sweet! put a picture of me on your wall!!

  • lol i got an exam to. cept its today >.> was reviewing until my friend told me to check out the vids. they helped a lot man

  • hahha, well, i hope the video was not 'too little... too late'! good luck on your exam.

  • yooou the maaan !(factorial)

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