Added: 4 years ago
From: TheCrazyBud
Views: 57,782
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  • most people don't what an ammeter is. That is true.

  • KW LOAD= (Kh)(Revs )3600 / 1000(Time)

    As simple as that guys. Your load = Kh times amount of revs counted times 3600seconds (sec in an hour) all devided by the quotient of 1000(Kilowatts) times the time recorded to get the counted revs.

    This changes if you have CT (current transformers) and a DK (Dial constant) other than 1.

    The DK is a multiplier for the dials. If you have a DK of 2 then the register is showing 1/2 the actual usage and must be multiplied by 2.

  • /watch?v=GoT2Epl7sGM

  • that was so fresh dude thanks a grip

  • Hi..

    Is your method and does your "calculator" work for other countries as well? I am from the Philippines..

  • your website has expired!

  • hey meterguy!  i bought a device that reduced my power by 40% want to know more ASK me

  • You forgot to include the refrigerator in your running equipment.

  • Is this for the ppl who don't have the knowledge to remove their panel cover and amp clamp the service legs? Because I don't understand why a homeowner needs to know precisely what their running wattage is. Needless to say I am heading outside to try this and compare it to my amp clamp to see how accurate it is. But I'm still scratching my head as to why it is needed for the average homeowner.

  • Your clamp on meter measures the current (of course). The meter records real power. volts X amps does not necessarily show the real power due to reactive loads. Therfore your finding probably will not match with the meter.

  • if you know watt (humor) your running wattage is for each leg shouldn't that be the same as watt (couldn't resist) your meter is reading? and still why would an average homeowner need to do this?

  • Not every home owner has an ammeter and is comfortable clamping an ammeter around a service conductor.

    In addition, the homeowner would have to know when to clamp both hot legs of a 240 V service and divide the sum of the amperage measured in each leg by 2 to get the overall amperage load or to just clamp the hot leg of a 120 Volt load.

    They would have to know that I X E = P to get the apparent power.

    Clamping would not be accurate as a bill is based on true power and not apparent power

  • your ammeter is basically a current transformer showing amperage for each leg. clamp each leg individually, / your voltage for each leg and add both wattages together, giving your total wattage at time of metering. if you know your Kh premium, you can figure out your utility cost at that very moment of metering. As your usage varies so will your amperage. Making it vary difficult to track. Which is why your power company uses a wattmeter.

  • Like I said over a year ago though, it's not very practical for any homeowner or electrician to do this. So the question is basically moot.

  • How do we know the "test equipment" wasn't rigged up somehow?

  • Cool, I didn't know meters were so interesting.

  • Very cool and informative vid. i'll have to give that a shot. Thanks for shareing!

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