Calculus: Integrals 2

[naruto7904]

this is WSOME HES HAND WRITING IS SO CLEAR

[grounnyJr]

i think the last excersise is wrong.....

is -90º not 90º as it says here.....

[momoon07]

he is greaaaaaaaaaaaaaaat

[SaMan966]

wow!! my concepts are Now clear!!!

[SaMan966]

Wow!!!! cleared my concepts!!

[NeoZC]

Your teaching skills are awesome!! I COMPLETELY understand everything you're doing. When my professor teaches i have absolutely no idea what he does and he does 40 problems but out of those 40 he cant explain any. I learn 10 times more with one of your videos than in 3 hours in my calc class. You're awesome, keep up the awesome work, you're helping a lot of people.

[rio809]

this guy is the best!!!!! thank you!! all the way from Puerto Rico!!!

[gatorflight]

Haven't done Calculus in a few years and this professor gives a great refresher.

[marievzalm]

SOOOO helpful =)

[Alpha24985]

the last two integrals can be solved by the trigonometric substitution technique. in the 1st of them suppose that [ x = sin u ] => dx = cos(u) . du. Hence, the integral becomes => int [ (cos u du) / (1 - (sin u)^2)^0.5] ... since 1 - (sin u)^2 = (cos u)^2 , the integral becomes => int [ (cos u du) / cos u ] = int (du) = u = arcsin x "from the original assumption"... while in the 2nd of them the appropriate supposition is [x = tan u] => dx = (sec u)^2 du & 1 + (tan u)^2 = (sec u)^2

[magusdch]

@Alpha24985

you are correct but sometimes it is much easier to recognize an integral by observation instead of doing all the math.

[MsWtfisgoingon]

lol at 0:17 jumpy eye brows :D

[blanquis019]

i need learn more english :/ .... but tanks..

[nunezgunner]

Thanks from Honduras. :D

[kaileyhuot]

Clear, effective teaching style. Very helpful!!

[guitarlearner89]

guys what does this question wanna find or prove??? i understand the step dont understand generally what he wanna do?

[salvadorwill]

Thank you so much for making these videos, that are lifesavers!

[dianelly]

GOD bless u

[HipAshTree]

You are absolutely AMAZING. Thank you. Thank you. Thank you.

[ndoctor27]

i learn more in these 10 minute sections than i do all week in my 12th grade calc class

very useful

[silvercrownt]

Awesome, really helped me in self based studies

[blackdefender]

I got amazed..never did our teacher taught us the derivation of the formula for the Inverse Trigonometric Derivatives..good job Sir!

[Skygooose]

You are the man.

[82tommylew]

Thanks man. You have mastered the are of teaching. My professor has learned calc. well. Good for him. I need to learn this crap!

[helopilot1977]

You are a blessing to a lot of people! Thank you so much for using your gift of teaching, and making it available to everyone. Now, I feel like I can do well in calc. I love all the videos!

[axlxavier]

Until now, this is the best video about integrals I've ever seen.....thanks

[evertonesf]

Thanks, from Brazil... Great!!!

[seanyb32]

i like this guy, my teacher is very patronising - massive wanker!!!!!

thank u for bringing this new guy into my life

[macleous]

You are far superior to my calculus teacher. She feels that the original derivations of formulas are unimportant. Thanks so much for the help.

[shadowsin500]

awsome!

[ssaa444]

helpful and Five stars

[maricam16]

what about definite intregrals??? is this for definite integrals too???

[wesselbindt]

Stop trolling.

[pimpimbulldog]

The formula is true for intervals that do not contain the value pi/2 because the limit of tan(x) to pi/2 is + or - infinite. for example you could use it for [0,pi/4],[-pi/3,pi/3] and so on.

[d00meD]

@pimpimbulldog in many cases, the appearance of asymptotes in integrals is remedied by using formulas for improper integrals...essentially this means you are finding the limit of the areas on both sides of the undefined value and adding them together

[bluelimemonkeys]

the two example problems at the end involve definite integrals...

[tranquilitywithin]

thank you very much sir you have got a brilliant teaching style

regards;

(student of biotech & info )

____________________

[jerran09]

yeah its great ive learn a lot...

[isam1335]

nice ! XD I love calculus so much Now ! XD

[joannamarcos79]

thanks so much, this makes learning calculus so much easier to understand especially when some teachers don't explain it well and move on to a different concept

[LEONNIGHT7]

Im speak spanish but finally im understanding man, haha.

Thanks champ...

Five stars.

[MyHugestFan]

me too. I'm from mexico and i always end up studying math from youtube because i always skip classes.

Thank you for your videos :)

[1aaronaaron1]

thats helpful but i need a miracle... :(

[PrepUS214]

bet this guy has a Phd in math and neat handwriting

[theanimefreakazoid]

Simply beautiful.

[pixxyspiffblues]

Thank you so much for doing these, I have a Calculus midterm tomorrow and these REALLY helped.

[wildstar43]

Thank you sir, I wish that you were my calculus 1 & 2 professor.

[BremenKoenig]

You make learning calculus an absolute treat!

Thank you to the nth degree!

[0550269106]

Thank you very much teacher ,and I appreciate it very much .

KEEP IT UP

[buddhika216]

Thanks!

[mynameisnotanumber]

Thanks for showing how to get the trig formulas, that really helped me out. Subscribed!

[Dark2Lnk]

sensei

[josuelillo1]

you are the best!!!!!!!!!!! if my professor would explain this like u it would be a lot more better!!!!!!!!!! thanks man!!!!!!!!

[buddhika216]

i wish my professor spoke english!

[260209]

i'll really appreciate if u follow the conditions, i mean when we teach maths we must have to be carefull abt denominator .......... thnx.

[joshatube]

God! I hope i remember this stuff when i encounter them on the exam!

Good Luck to me.

[gcash2009]

hey uncle, another great video u did here. in the beginning i almost got confused with ur notation of inverse sin x as sin-1 x... since im used to writing arc sin x... but well, it was self explaining :) good job. thanks.

[ffddssaavvccxxzz]

many thanks for you sir, this is the best work, i breacheat

[rakolman]

excellent

[midwestautowerks]

good stuff

[omfgnoel]

You are a life saver!! Thank you for putting in so much effort in helping people that really need it! Keep up the good work :D

[thankxbutno]

This guy is to awesome!!!

I love how you are very smiley...haha

[kevinmm20]

Where does this guy teach? I want to go where ever that is.

[Howboutthinking]

I Love You...

[teawithsu]

he makes me so hot in a really nice but bad way.

[gillent]

There's good AP Calculus help online on the mathnetap website

[lilslant]

why couldn't you be my calc. teacher?!! Your students must be soo lucky...

[1n1ee]

this guy's handwriting is amazing O_O...

[MSI2k]

This guy is smooth as the marker he's using.. good stuff!

[jacobbis4lovers]

This stuff is so confusing...

[jdbarbour804]

I wish i could think this clearly while taking a noncalulator test with less than 50 minutes...

[truazn0409]

i know it sucks. during class im able to do everything but during a test, i feel so time pressured and just forget everything

[jdbarbour804]

Amen bro.

[aznmasterx]

indeed

[BTNH108464]

you don't need a calculator to do what he's doing though.

[DmitriTheWise]

i find the easiest way to do any test when i'm short on time is to rush through it as fast as i can, and then make it better with the time remaining.

[gransahai]

i really found this video insightfull . Do you have any videos on area under a curve ? and volume under a curve ? thank you .

[4Teddybears]

I need help. How do I integrate this?

Y=Y0 * e^kx

"Y0" is the value of Y at the time when x is equal to 0.

e is the number 2.718(to 4 significant figures) and is raised to the power of a constant k, multiplied by x.

Help would be greatly apreciated =D

[cubencis]

use substitution: so y= y(0)*e^kx, [note; in this problem, when x=0 y=1- so y(0) is 1). let u= 1 (y(0)) let dv= e^kx therefore du is 0 and V= e^kx + C so plug it into the formula : S(integral) udv= uv- S(integrl) vdu...

[BernardoDW]

awesome ! :D no need to memorize 'em all now :D

[Stano87]

Beautifully, plainly explained.

[akd4ivt]

your my hero

[lillyvalleys]

I'm a little confused (it could be that I haven't slept much :D )

If 6*tan^-1 (sqrt3) then it's 6*1/tan(sqrt 3) --> 6 * 3/pi

I'm missing something here?

Thank you

Rosanella

:-)

[rexpro02]

cool work

[danieloreto]

The video is perfect, i just want to point out that if we use the notation used in the video for the inverse trigonometric functions the student might confuse the inverse sine function with 1 over sin x. Its always better to use Arcsin to denote the inverse sine, and also that is the notation used in some CAS like wolfram mathematica. good luck!

[jeanotho]

thanks for everything !!!

[bigDeeOT]

Wow I just gone done with calculus. I really wish I knew you when I was taking calculus.

[JackEffenBauer]

i'm going to watch all your vids on calc over the weekend...too bad i have a test on friday T_T

Your vids are great!

[chemicalculus]

I remember how to get the derivative of the inverse tangent function or arctanx. I remember i did derived it during the summer before taking calculus. :) The hint of doing the derivation is just mentioning the trig identities so we can make substitutions on the variables. man, calculus is tough too.

[curioustoknow123]

how did you get : if y=1/tanx them tang y = x

[maylien]

Another winner!

[popeye135]

This is very good

[SupraJZGTE]

not bad...put up a video for Calc 3 and Differential Equations :)

[Stung5]

Yes PLease, i agree

[rohano]

you saved my butt in calc!!! thank you

[fushinotori1]

omfg u just saved my ass for tomoras final any way i can get u to do polar and perametrics

[andyilpadrino]

great job thank you

[Hithran]

more videos on integration would be nice

[209507]

The area of the region bounded by the curv

y = e^2x, the x-axis, the y-axix and the line x = 2 is equal to what?

what is the answer...Would you please explain me?

[k0tiak]

~26.799...

The antiderivative (integral) of e^2x is (1/2*(e^2x)). If you were to take the derivative of e^2x you would get y' = 2e^2x. y'' = 4e^2x, y''' = 8e^2x...so reversing the process also would mean that you have to remove the coefficient. (i.e. the 2, 4 or the 8).

When you draw a simple graph, you will see that you are being asked to find the area under the curve between the intervals 0 to 2.

(.5(e^(2*2)) - .5(e^(2*0))) = ~26.8

[Mediczmofo]

Heheheh I like the shirts he wears in his videos! And the lectures of course!

[pointz3ro]

Sir, excellent job. I have truly enjoyed your short lectures, please continue to post more examples and explanations, thank you.

[alexlaz]

great.

[Iwanthax]

Keep it up good sir! by far the best explanations for calculus ever!

[ari102791]

very good video, with great explanations