Remainder Estimate for the Integral Test

[KByunish]

GOD I LOVE THIS GUYY!!

[kittwan42]

It is all so clear now! =,D

[aznlalaland]

Please do a video about lower integrals and upper integrals. I know the definitions but the definitions are very contradictory!

[Ladarzak]

Wow, this is the first time one of your videos has been confusing for me.  All the erasing. Too bad. Every other video has been awesome, though.

[theotheroleander]

you are soooo good at explaining calculus thank you!!!!

[SpittenHotFire]

Does the series have to be continuous, positive and decreasing in order to use the Remainder Test?

[aka3740]

Thanks bro

[omfgcheez]

Because this series starts with n=2, wouldnt the integral be from 11->infinity? I know it's a very small thing, I just want to make sure I'm understanding it correctly lol

[AKHayleyO]

@omfgcheez i thought it would be from 12 to infinity

[AKHayleyO]

@AKHayleyO wait.... nevermind

[VanNoortMusic]

So instead of having ln(x) squared, we're gonna have YOU squared :P lol

[HowToDo92]

wow...u r a neat freak!! lol i dunno how u write it soo clean and neat. thanks for the vids

[byrne342]

fantastic video, couldn't express my gratitude enough. watching this video once, then tried the problem i was stuck on and got it my first time! from absolute confusion to a right answer, thank you

[Blam0492]

PatrickJMT you are THE LIFE SAVER! You have no idea how much I have suffered from my professor's nonsensical lectures and explanations. THANK YOU for finally clearing the clouds!

[denokindo]

Great job P. I know you would be doing something more prestigious than posting vids but your help is actually building the world right from youtube!

[dorood]

these integration test vids should be part of your series playlist! it would make it easier to find them :)

[patrickJMT]

@dorood yea, i know. it seems like keeping things organized takes more time than actually making the vids!! and if there is one thing i hate to do, it is to organize things.... zzzzzzzzzzzzzz.........

[SGWyoshi]

I have an exam on series later tonight

thanks for the help :D

[talya222]

do u know the technique for finding the remainder estimate by doing something like (if you were using n=10) finding the coefficient of the x which is to the 11th or somehting, so its like the llth derivative over 11 factorial, and then you do something else....lol, obviously im not veryfamiliar with it, but if you know wat im talking about, could you post a vid on it?

[talya222]

@talya222 o woops, u already have a vid on that, haha, nevermind

[valeovir]

not to be nit picky but since your initial series starts at n=2, then wouldn't the 10th term be n=11 and not 10?.

love your vids

[ellenhutchxx]

that's very helpful...you are good at explaining.

A visual proof of the remainder estimate would also be helpful! The one in my textbook makes no sense...

[iluvdarrenNB]

Thank you so much!

[soonertiger2012]

Very helpful video! Thanks for posting it. :)

[Rickmand]

Shouldnt we integrate with 12 as the lower bound instead, since the series starts at 2?

[GRX13]

Integration is like magic!

[patrickJMT]

it is very clever!!

[driftx2]

Thank you.. got a test today over this stuff xD

[bazblo]

I really appreciate you posting this.

[patrickJMT]

no worries... someone asked for it, and i can not remember if it was you or not.

in any event, hope it helps