I may have missed it in the previous lectures, but can someone remind me why the eigenvalues of the inverse of A are simply the reciprocals of the eigenvalues of A?
These lectures are great and I really respect MIT for doing this, much more so than other high level universities, but shit, man. How hard is it to make a video of a dude talking at a blackboard? It would probably take less than 5 minutes to put a little bit of gain on the audio file and for over 5,000 views I'd say those 5 minutes would be well spent.
Finals. Only one left and it's Christmas.
kotofu 2 months ago
thanks professor gilbert
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BlendersWitantoCom 8 months ago in playlist MIT 18.06 Linear Algebra, Spring 2005
I may have missed it in the previous lectures, but can someone remind me why the eigenvalues of the inverse of A are simply the reciprocals of the eigenvalues of A?
zkhandwala 1 year ago
@zkhandwala
(A' represents A inverse)
AX=λX
A'AX=A'(λX)
IX=λ(A'X)
(1/λ)X=(A'X)
A'X=(1/λ)X
That last equation is just like the first, it's an eigenvector-equation. The eigenvalue is now (1/λ). This only holds if A is invertable, of course.
yuppygoat 1 year ago
This guy is wayyyyyyyyyyyyyyyy better then my Linear Algebra professor. In the first 5 minutes I've learned more then I did all semester.
jae44 1 year ago
These lectures are great and I really respect MIT for doing this, much more so than other high level universities, but shit, man. How hard is it to make a video of a dude talking at a blackboard? It would probably take less than 5 minutes to put a little bit of gain on the audio file and for over 5,000 views I'd say those 5 minutes would be well spent.
DBangaDon 1 year ago 2